Question

What are the solutions of x2 - 2x + 26 = 0 ?

Answer 1

Answer:

B

Step-by-step explanation:

Given

x² - 2x + 26 = 0 ← in standard form : ax² + bx + c = 0 : a ≠ 0

with a = 1, b = - 2, c = 26

Use the quadratic formula to solve for x

x = ( - (- 2) ± $\sqrt{(-2)^2-(4(1)(26)}$ ) / 2

  = ( 2 ± $\sqrt{4-104}$ ) / 2

  = ( 2 ± $\sqrt{-100}$ ) / 2

  = ( 2 ± 10i ) / 2

  = 1 ± 5i

Solutions are x = 1 + 5i or x = 1 - 5i → B