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3 years ago

The slope of a line is 0 and it contains the point (3,1)

Mathematics

1 answer:

Sedaia [141]3 years ago

3 0

Answer:

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

<em>m</em><em> - slope</em>

<em>(x₁, y₁)</em><em> - point on a line</em>

We have <em>m = 0, (3, 1) → x₁ = 3, y₁ = 1</em>.

Substitute:

$y-1=0(x-3)$

$y-1=0$ <em>add 1 to both sides</em>

$y=1$

Other method.

If the slope is equal 0, then it's a horizontal line.

The equation of a horizontal line: <em>y = a</em>.

We have the point on a line (3, 1) → x = 3, y = 1.

Therefore the equation is <em>y = 1</em>.

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Nick wanted to determine the length of one blade of a windmill. He stood at a point on the ground 440 feet from the windmill's b

mafiozo [28]

Answer:There are two right triangles. You need to find the opposite side (the height) of each of them. The difference between the two is the height of the blade, x.

You know the adjacent, 440, and you are looking for the opposite, so you need to use tan for both.

tan (30) = y / 440

y = 440 * tan (30) = 254.034...

tan (38.8) = z / 440

y = 440 * tan (38.8) = 353.769.--

353.8 - 254.0 = 99.8 = 100 feet.

Step-by-step explanation:

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1 year ago

Write a linear equation to represent the line shown on the graph

sveticcg [70]

Answer:

y=-3x+4

Step-by-step explanation:

it's negative bc the slope is going from left to right. you just have to do rise over run to find the slope.

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3 years ago

Which factor contributed most to the decline of the buffalo population in the West in the late 1800s?

Nikitich [7]

Manifest destiny, as many settlers moved west after the Louisiana purchase to claim land that the U.s government was handing out. With a sudden influx of settlers and people needing to eat/make money off of their pelts. The buffalo population declined

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3 years ago

Read 2 more answers

What is the answer to this question I can’t work it out Ni=n02(yi-yo)/t2

mr_godi [17]

Changing the subject of an equation involves solving for another variable in the equation

The equation of t is $t=\frac{\sqrt{y_i-y_o}}{N}$

<h3>How to change the subject of the equation</h3>

The equation is given as:

$N=\sqrt[2]{\frac{y_i-y_o}{t^2}}$

Rewrite the equation as:

$N=\sqrt{\frac{y_i-y_o}{t^2}}$

Evaluate the square root of t^2

$N=\frac{\sqrt{y_i-y_o}}{t}$

Multiply both sides by t

$Nt=\sqrt{y_i-y_o}$

Make t the subject, in the above equation

$t=\frac{\sqrt{y_i-y_o}}{N}$

Hence, the equation of t is $t=\frac{\sqrt{y_i-y_o}}{N}$

Read more about subject of formula at:

brainly.com/question/657646

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2 years ago

Solve the equation x+3/x-4 = x-5/x+4

Serga [27]

Answer:

$\large\boxed{x=\dfrac{1}{2}}$

Step-by-step explanation:

$\dfrac{x+3}{x-4}=\dfrac{x-5}{x+4}\\\\\text{Domain:}\ x-4\neq0\ \wedge\ x+4\neq0\\\\x\neq4\ \wedge\ x\neq-4\\\\D:x\in\mathbb{R}-\{-4,\ 4\}$

$\dfrac{x+3}{x-4}=\dfrac{x-5}{x+4}\qquad\text{cross multiply}\\\\(x+3)(x+4)=(x-4)(x-5)\qquad\text{use FOIL}\ (a+b)(c+d)=ac+ad+bc+bd\\\\(x)(x)+(x)(4)+(3)(x)+(3)(4)=(x)(x)+(x)(-5)+(-4)(x)+(-4)(-5)\\\\x^2+4x+3x+12=x^2-5x-4x+20\qquad\text{combine like terms}\\\\x^2+(4x+3x)+12=x^2+(-5x-4x)+20\\\\x^2+7x+12=x^2-9x+20\qquad\text{subtract}\ x^2\ \text{from both sides}\\\\7x+12=-9x+20\qquad\text{subtract 12 from both sides}\\\\7x=-9x+8\qquad\text{add}\ 9x\ \text{to both sides}\\\\16x=8\qquad\text{divide both sides by 16}\\\\x=\dfrac{8}{16}\\\\x=\dfrac{8:8}{16:8}\\\\x=\dfrac{1}{2}\in D$

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3 years ago