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Tasya [4]
4 years ago
6

Please help me with this question thank you

Mathematics
2 answers:
Fantom [35]4 years ago
8 0
If the answer is an equation then it is:
x=(4y+15)/(5-3y)
LenaWriter [7]4 years ago
5 0

Answer:

If the answer you want is the value in terms of x then it is:

 x  = ( 4y - 3xy + 15 ) / 5  

Step-by-step explanation:

5 ( x - 3 ) = y ( 4 - 3x )                              Distribute

  5x - 15 = 4y - 3xy                                  Add 15 on both sides        

        5x  =  4y - 3xy + 15                          Divide 5 on both sides

          x  = ( 4y - 3xy + 15 ) / 5                        

                 

            <em><u>   OR     </u></em>    \frac{4y\:-\:3xy\:+\:15\:}{5}

<h3><u><em></em></u></h3><h3><u><em>Please rate this and please give brainliest. Thanks!!! </em></u></h3><h3><u><em>Appreciate it! : ) </em></u></h3><h3><u><em>And always, </em></u></h3><h3><u><em>SIMPLIFY BANANAS          : )</em></u></h3><h3><u><em></em></u></h3>

<u><em></em></u>

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at a putt-putt golf course there are 50 yellow golf balls, 45 red golf balls and 65 blue blue golf balls. What ratio compares th
tatuchka [14]
65:160 because you add all the golf balls together (including blue) and get a total of 160 and then compaire that to 65
4 0
3 years ago
What are the zeros (x-intercepts) of the function y - 2x2 +7x+3?
xeze [42]

Step-by-step explanation:

b+/-(√b^2-4ac)/2a

7+/-(√7^2-4(2)(3)/2(2)

=-3 or =-1/2

8 0
3 years ago
Find the total travel time: Depart 11:00 am CST Arrive 7:00 pm PST.
arsen [322]
Answer: is 10 hours
6 0
4 years ago
In the binomial probability distribution, let the number of trials be n = 4, and let the probability of success be p = 0.3418. U
Lorico [155]

Answer:  (a) 0.105   (b) 0.014  (c) 0.119

Step-by-step explanation:

Binomial probability distribution formula :

P(X=x)= \ ^nC_x p^x(1-p)^{n-x} , where x= number of successes, p= probability of success in each trial, n= number of trials.

Given: n= 4 , p= 0.3418

(a)

P(X=3)=\ ^4C_3(0.3418)^3(1-0.3418)^1\\\\=(4)(0.026282946626)\\\\\approx0.105

(b)

P(X=4)=\ ^4C_4(0.3418)^4(1-0.3418)^0\\\\=(1)(0.013648604006)\\\\\approx0.014

(c)

P(X= 3\ o\r X=4)= P(X=3) +P(X=4)\\\\=0.105+0.014\\\\=0.119

8 0
3 years ago
If f(1) = 0, what are all the roots of the function f(x)=x^3+3x^2-x-3? Use the Remainder Theorem.
Sophie [7]
There's no if about it, 

f(x)=x^3+3x^2-x-3&#10;

has a zero f(1)=0 so x-1 is a factor.   That's the special case of the Remainder Theorem; since f(1)=0 we'll get a remainder of zero when we divide f(x) by x-1.

At this point we can just divide or we can try more little numbers in the function.  It doesn't take too long to discover f(-1)=0 too, so  x+1 is a factor too by the remainder theorem.  I can find the third zero as well; but let's say that's out of range for most folks.

So far we have 

x^3+3x^2-x-3 = (x-1)(x+1)(x-r)

where r is the zero we haven't guessed yet.  Again we could divide f(x) by (x-1)(x+1)=x^2-1 but just looking at the constant term we must have

-3 = -1 (1)(-r) = r

so

x^3+3x^2-x-3 = (x-1)(x+1)(x+3)

We check f(-3)=(-3)^3+3(-3)^2 -(-3)-3 = 0 \quad\checkmark

We usually talk about the zeros of a function and the roots of an equation; here we have a function f(x) whose zeros are

x=1, x=-1, x=-3

8 0
3 years ago
Read 2 more answers
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