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2 years ago

15

The picture shows a box sliding down a ramp.

2 answers:

forsale [732]2 years ago

8 0

In your question where as the picture shows a box sliding down a ramp and ask to calculate the distance, in feet, that the box has to travel to move form point A to point C and the best answer would be 12 cosec 65. I hope you are satistfied with my answer and if you need some clarification, please feel free to ask for more

bija089 [108]2 years ago

6 0

Answer:

$AC=12cosec(65\°)\ ft$

Step-by-step explanation:

we know that

In the right triangle ABC

$sin(65\°)=\frac{AB}{AC}$

In this problem we have

$AB=12\ ft$

Substitute and solve for AC

$sin(65\°)=\frac{12}{AC}$

$AC=\frac{12}{sin(65\°)}$

Remember that

$cosec(65\°)=\frac{1}{sin(65\°)}$

substitute

$AC=12cosec(65\°)\ ft$

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Round 66,681 to the nearest ten thousand

kolezko [41]

Answer:

70,000

Step-by-step explanation:

66,681 is closest to 70,000 rather than 60,000.

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2 years ago

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What is the standard form 2x-3x2=5??

tigry1 [53]

35 because 2x-3.45.there is the answer 35

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2 years ago

Find the linear approximation of the function g(x) = 3 1 + x at a = 0. g(x) ≈ Correct: Your answer is correct. Use it to approxi

EleoNora [17]

Answer:

$3.296x+3$

2.835

3.330

Step-by-step explanation:

$g(x) = 3^{1+x}$

Let the linear approximation be L(x) at a = 0. This is given by

$L(x) = g(a) + g'(a)(x-a)$

$g'(x)$ is the derivative of $g(x)$ . To find this, we use the form

If $f(x) = a^x$ , then $f'(x) =a^x\ln a$

By doing this and applying chain rule for the power (which is a function of x), we have

$g'(x) = 3^{1+x}\ln 3$

Then

$g'(0) = 3^{1+0}\ln 3 = 3.296$

Also $g(0) = 3^{1+0} = 3$

Hence $L(x) = 3+(x-0)\times3.296 = 3.296x + 3$

For $3^{0.95}$ , $1+x = 0.95$ and $x=-0.05$

Using this in $L(x)$ ,

$3^{0.95} = 3.296(-0.05) + 3 = 2.835$

For $3^{1.1}$ , $1+x = 1.1$ and $x=0.1$

Using this in $L(x)$ ,

$3^{1.1} = 3.296(0.1) + 3 = 3.330$

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3 years ago

Left parenthesis 5 plus 2 square root of 6 right parenthesis squared = a plus b square root of 6 then the value of a and b are

Ganezh [65]

Answer:

The values of $a$ and $b$ are $33$ and $\frac{20\sqrt{3}}{3}$ , respectively.

Step-by-step explanation:

The statement is equivalent to the following mathematic expression:

$\left(5 + 2\sqrt{2})^{2} = a + b\cdot \sqrt{6}$ (1)

By definition of the perfect square trinomial:

$25 + 20\cdot \sqrt{2} + 8 = a + b\cdot \sqrt{6}$

$33 + 20\sqrt{2} = a + b\cdot \sqrt{6}$

And by direct comparison we have the following system:

$a = 33$ (2)

$b\cdot \sqrt{6} = 20\sqrt{2}$ (3)

By (3), we solve for $b$ :

$b = \frac{20}{\sqrt{3}}$

$b = \frac{20\sqrt{3}}{3}$

The values of $a$ and $b$ are $33$ and $\frac{20\sqrt{3}}{3}$ , respectively.

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3 years ago

Part of the graph of the function f(x) = (x – 1)(x + 7) is shown below.Which statements about the function are true? Select thre

sertanlavr [38]

The statements about the function that are true are

The vertex of the function is at (–3,–16).
The graph is increasing on the interval x > –3.
The graph is positive only on the intervals where x < –7 and where x > 1.

<h3>How to interpret the graph?</h3>

The equation of the graph is given as

f(x) = (x - 1)(x + 7)

The graph of the function is added as an attachment

On the graph, we have

Vertex = (-3, -16)

This is so because the graph has a minimum point of (-3, -16)

Also, the graph crosses the x-axis at x = 1 and x = -7

This means that the graph is positive at x >1 and x >-7

Because the vertex is a minimum, the graph is increasing at the left of its symmetry i.e. x > -3

Read more about quadratic functions at

brainly.com/question/14933288

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1 year ago