Is 12.655 greater than 13.6

Which of the following is a polynomial?<br> ОА. х2 - 1<br> ов. - + 2<br> ОС. 4-2<br> )

BARSIC [14]

Answer:

Step-by-step explanation:

C

5 0

4 years ago

Read 2 more answers

What is the slope of the line that contains these points?

nikklg [1K]

Answer:

3

Step-by-step explanation:

From the table, we know at least 2 ordered pairs. We can use the slope formula on any 2 ordered pairs on the table to get 3.

3 0

3 years ago

-5 (p+2)=2 (2p-15)+p

Bess [88]

$-5 (p+2)=2 (2p-15)+p$

$-5p-10=4p-30+p

$ $\text{Expand}$

$-5p-10=5p-30
$

$-10=5p-30+5p
$ $\text{Add 5p to both sides}$

$-10=10p-30

$

$-10+30=10p
$ $\text{Add 30 to both sides}$

$20=10p
$

$\dfrac{20}{10}=p$ $\text{Divide both sides by 10}$

$p=2$ $\text{Solution}$

6 0

3 years ago

1. A rabbit can hop 6 feet in 2 seconds and 12 feet in 4 seconds. If the number of feet varies directly with the time the rabbit

kykrilka [37]

Answer: The rabbit is hopping at 3 feet/ sec in speed

Step-by-step explanation:

Step 1

Let the The number of feet of the rabbit be expressed as N

AND time rabbit spends hopping can be expressed as t

From the question, The number of feet varies directly with the time rabbit spends hopping can be expressed as

N α t

Let us introduce a constant of proportionality ,S which represents speed in this case, we now have that

N = St

STEP 2 -- SOLVING

If the rabbit hop 6 feet in 2 seconds, Then speed =

N = St

6= S X2

S = 6/ 2

S = 3

also

If the rabbit hop 12 feet in 4 seconds, Then speed =

N = St

12= S X 4

S = 12/ 4

S = 3

Also recall

that Speed = Distance / time

Pluging the values in the first case,

speed = 6 feet/ 2 secconds = 3 feet/ seconds

in the second case

Speed= 12 feet/ 4 second s= 3 feet/ secs.

5 0

3 years ago

If discount rate is 12%, the present value of Rs X recieved at the end of each year for the next five years is equal to

myrzilka [38]

Answer:

Present Value = $X [\frac{1}{(1 + 0.12)^{1} } + \frac{1}{(1 + 0.12)^{2} } + \frac{1}{(1 + 0.12)^{3} } + \frac{1}{(1 + 0.12)^{4} } + \frac{1}{(1 + 0.12)^{5} } ]$

Step-by-step explanation:

To find - If discount rate is 12%, the present value of Rs X received at the end of each year for the next five years is equal to .... ?

Solution -

We know that, formula for finding the Present vale is given by

Present value = Future value / (1 + r)ⁿ

where r is the rate of interest

and n is Number of periods

Now,

Here in the question, we have

r = 12% = 12/100 = 0.12

n = 5

Also, Given that, we have received Rs X at the end of each year

So,

Present Value = $\frac{X}{(1 + 0.12)^{1} } + \frac{X}{(1 + 0.12)^{2} } + \frac{X}{(1 + 0.12)^{3} } + \frac{X}{(1 + 0.12)^{4} } + \frac{X}{(1 + 0.12)^{5} }$

= $X [\frac{1}{(1 + 0.12)^{1} } + \frac{1}{(1 + 0.12)^{2} } + \frac{1}{(1 + 0.12)^{3} } + \frac{1}{(1 + 0.12)^{4} } + \frac{1}{(1 + 0.12)^{5} } ]$

⇒Present Value = $X [\frac{1}{(1 + 0.12)^{1} } + \frac{1}{(1 + 0.12)^{2} } + \frac{1}{(1 + 0.12)^{3} } + \frac{1}{(1 + 0.12)^{4} } + \frac{1}{(1 + 0.12)^{5} } ]$

7 0

3 years ago