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Alenkinab [10]
3 years ago
5

Is 12.655 greater than 13.6

Mathematics
1 answer:
OleMash [197]3 years ago
6 0

nooooooooooooooooooooooooo

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For the level 3 course, exam hours cost twice as much as workshop hours, workshop hours cost twice as much as lecture hours. How
natulia [17]
<h2>Answer</h2>

Cost of lectures = $7.33 per hour

<h2>Explanation</h2>

Let e the cost of the exam hours

Let w be the cost of the workshop hours

Let l be the cost of the lecture hours.

We know from our problem that exam hours cost twice as much as workshop, so:

e=2w equation (1)

We also know that workshop hours cost twice as much as lecture hours, so:

w=2l equation (2)

Finally, we also know that 3hr exams 24hr workshops  and 12hr lectures cost $528, so:

3e+24w+12l=528 equation (1)

Now, lets find the value of l:

Step 1.  Solve for l in equation (3)

3e+24w+12l=528

12l=528-3e-24w equation (4)

Step 2. Replace equation (1) in equation (4) and simplify

12l=528-3e-24w

12l=528-3(2w)-24w

12l=528-6w-24w

12l=528-30w equation (5)

Step 3. Replace equation (2) in equation (5) and solve for l

12l=528-30w

12l=528-30(2l)

12l=528-60l

72l=528

l=\frac{528}{72}

l=\frac{22}{3}

l=7.33

Cost of lectures  = $7.33 per hour



3 0
3 years ago
Read 2 more answers
a volley ball player servers the ball. The ball follows a path given by the equation y=-0.01x^2+0.5x+3 where x and y are measure
dolphi86 [110]

Answer:

(a)

Distance from player should be 13.82 feet or 36.2 feet

(b)

The ball will go over the net

Step-by-step explanation:

we are given

The ball follows a path given by the equation

y=-0.01x^2+0.5x+3

where

x and y are measured in feet and the origin is on the court directly below where the player hits the ball

(a)

net height is 8 ft

so, we can set y=8

and then we can solve for x

8=-0.01x^2+0.5x+3

8\cdot \:100=-0.01x^2\cdot \:100+0.5x\cdot \:100+3\cdot \:100

800=-x^2+50x+300

-x^2+50x-500=0

x^2-50x+500=0

we can use quadratic formula

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

x=\frac{-50\pm \sqrt{50^2-4\left(-1\right)\left(-500\right)}}{2\left(-1\right)}

x=5\left(5-\sqrt{5}\right),\:x=5\left(5+\sqrt{5}\right)

x=13.82,x=36.2

So, distance from player should be 13.82 feet or 36.2 feet

(b)

we can plug x=30 and check whether y=8 ft

y=-0.01(30)^2+0.5(30)+3

y=9ft

we know that

height of net is 8 ft

so, the ball will go over the net


5 0
3 years ago
What is the length of leg s of the triangle below? A. 2.2 B. 4 C. 32 D. 4 E. 1.5 F. 16
stiv31 [10]

Answer:

s = 4

Step-by-step explanation:

Note that the triangle has 2 congruent base angles, both 45°

This means the triangle is isosceles with congruent legs, then

s = 4

4 0
3 years ago
The bottom of a ladder rests on the ground and the top of the ladder rests against a wall. The ladder forms a 63° angle with the
Eddi Din [679]

Answer:

the one you picked was right.

Step-by-step explanation:

if 63° was the angle and the 12 was the side then "x" will be one the bottom. then you flip the fraction meaning 1/sin63° and x/12 and then multiply 12 on both sides. you will be left with x = 12/sin63°. sorry if that doesn't make sense

5 0
2 years ago
A local college recently reported that enrollment increased to 108% percent of last year. If enrollment last year was at 17,113,
Sever21 [200]
Answer=18,482 students

  17113        x
_______=_____
  100%      108%

Cross multiply
100x=<span>1848204
divide both sides by 100
x=18482.04
Round to the nearest whole number
x=18,482 students</span>
6 0
3 years ago
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