Answer:Assuming all three, we shall find that each of the relations in 3:14 leads to a ... Then by 3:15 the relations AD//BC and AB||DE imply AD//CE, which excludes ... From 2:72, 3:11, 3:14, and 3:16 we deduce 3:19 If A, B, C are three distinct ... a point D lies between X and Y in AB/C if it belongs to XY/C, that is, if XY||CD
Step-by-step explanation:
<u>Answer:</u>
Hence, Relation t is a function. The inverse of relation t is a function.
<u>Step-by-step explanation:</u>
We are given the relation as:
x: 0 , 2 , 4 , 6
y: -10 , -1 , 4 , 8
<em>Clearly from the y-values corresponding to the x-values we could see that each x has a single image (single y-value).</em>
Hence, the corresponding relation is a function.
Now we have to find whether the inverse of this relation is a function or not.
When we take the inverse of this function that is the y-values will behave as a pre-image and x-values as its image.
Hence we will see that corresponding to each y-value there is a unique image hence the inverse relation is also a function.
Hence, Relation t is a function. The inverse of relation t is a function.
Answer:
25. Not a solution
26. Yes a solution
27. y= 2/3 x
28. y=3x+16
Step-by-step explanation:
25. The solution to a linear equation is the point (x,y). To find if an (x,y) is a solution, substitute it into the equation and see if it works.
y=4x-4 and (8,3)
3=4(8)-4
3=32-4
3=28
False
Not a solution.
26. Repeat 25 to solve 26 with y=5x-5 and (0,-5)
y=5x-5 and (0,-5)
-5=5(0)-5
-5=0-5
-5=-5
True
Yes a solution.
27. This line crosses through the origin is proportional and therefore has the form y=mx. It also has a gentle slant meaning that is less than 1/2 and goes in a positive direction. This means it is y=2/3 x.
28. Use inverse operations to rearrange the equation.
y-3x=16
y=16+3x
y=3x+16
First, i put the equation in y=mx+b by dividing 2, since its 2y. since it’s perpendicular we’re talking about you switch the sides (opposite reciprocals). the rest should be self explanatory.
