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Answer:
The ratio of the number of atoms of gold and silver in the ornament is 197 : 1080.
Explanation:
Let the mass of silver ornament be x.
Mass of gold polished on an ornament = 1% of x= 0.1 x
Moles of silver =
Number of atoms = 
Where : 
= Avogadro number
Moles of gold =
Silver atoms =
Gold atoms =
The ratio of the number of atoms of gold and silver in the ornament:
= 197 : 1080
Answer:
because they cannot be seen by our naked eyes to make them visible we must use microscope.
Answer:
10.8 g
Explanation:
<em>A chemist adds 480.0 mL of a 0.169 mol/L aluminum chloride solution to a reaction flask. Calculate the mass in grams of aluminum chloride the chemist has added to the flask. Round your answer to 3 significant digits.</em>
Step 1: Given data
- Volume of the solution: 480.0 mL
- Concentration of the aluminum chloride solution: 0.169 mol/L
Step 2: Calculate the moles of aluminum chloride in the solution
We will multiply the volume of the solution by the molarity.
0.4800 L × 0.169 mol/L = 0.0811 mol
Step 3: Calculate the mass corresponding to 0.0811 moles of AlCl₃
The molar mass of AlCl₃ is 133.34 g/mol.
0.0811 mol × 133.34 g/mol = 10.8 g
