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2 years ago

Find the density of a cube on Earth that weighs 1.5 kg and has a side-length of 10 cm.

Chemistry

1 answer:

Inga [223]2 years ago

4 0

Answer:

1.5g/cm³

Explanation:

density=mass÷volume

mass= 1.5kg (change into g) = 1500g

volume of the cube = 10×10×10 = 1000cm³

density= divide 1500g÷1000cm = 1.5g/cm³

<h2>Density= 1.5g/cm³</h2>

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When 63.4 g of glycine (C2HNO2 are dissolved in 700. g of a certain mystery liquid X, the freezing point of the solution is 7.9

bearhunter [10]

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Depression in freezing point is given by:

$\Delta T_f=i\times K_f\times m$

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i= vant hoff factor = 1 (for non electrolyte)

$K_f$ = freezing point constant = $k^0C/m$

m= molality

$\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}$

$7.9^0C=1\times k_f\times \frac{63.4g\times 1000}{75.07g/mol\times 700g}$

$k_f=6.55^0C/m$

b) $\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}$

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$i=3.64$

Thus the van't Hoff factor for iron(III) chloride in X is 3.64

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