Step-by-step explanation:
P(t) = 12,000 (2)^(-t/15)
9,000 = 12,000 (2)^(-t/15)
0.75 = 2^(-t/15)
ln(0.75) = ln(2^(-t/15))
ln(0.75) = (-t/15) ln(2)
-15 ln(0.75) / ln(2) = t
t = 6.23
Answer: If you are solving for x, then thee is no solution
Step-by-step explanation:
Answer: The Pacing Method:
Use Edulastic to help convey weekly expectations and track student progress along the way
You can set up Edulastic to function as your check-in-tool with students, and Edulastic will help you in gathering student data during this process (#Edulasticforthewin!). This can help in estimating student participation grades and preparing reports to supervisors. It can also help with pacing and students staying on task.
When I was a high school science teacher I would structure “Check ins” with my students on written handouts that students had to present to me for my signature (upon meeting and discussing project updates, hearing feedback from me etc.). If I had access to Edulastic tools then, I could have instead coordinated these check ins digitally and privately using Edulastic. They could check-in on their own time, at home or at school. That makes things a heck of a lot more efficient than having students form a line waiting to talk to me at my desk! You can set this up to occur at the every other day mark, weekly mark, biweekly, or even monthly mark depending upon length and scope of a project in place.
Check out how this might look in Edulastic:
Step-by-step explanation:
The square root of 195 is 13. 195 squared (195×195) is 38,025. I do not know which way you needed it but I put both situations just in case.
Answer: The amount is $14794.39 and the interest is $9794.39
Step-by-step explanation: If you deposit <em><u>$5000</u></em><u> </u>into an account paying <em><u>7.5%</u></em> annual interest compounded yearly , how much money will be in the account after <em><u>15 years</u></em>?
To find amount we use formula:
A-P(1+r/n) n*t
A = total amount
P = principal or amount of money deposited,
r = annual interest rate
n = number of times compounded per year
t = time in years
P=$5000, r=7.5, n=1 and, t=15 years
After plugging the given information we have
A= $5000 (1+0.075/1)^1.15
A= 5000 *1.075^15
A=14794.39
To find interest we use formula A=P+I'
since A= 14794.39 and P=5000
we have: A=P+I 14794.39=5000+I
I= 14794.39 -5000
I=9794.39
