Answer:
1. S(1) = 1; S(n) = S(n-1) +n^2
2. see attached
3. neither
Step-by-step explanation:
1. The first step shows 1 square, so the first part of the recursive definition is ...
S(1) = 1
Each successive step has n^2 squares added to the number in the previous step. So, that part of the recursive definition is ...
S(n) = S(n-1) +n^2
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2. See the attachment for a graph.
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3. The recursive relation for an arithmetic function is of the form ...
S(n) = S(n-1) +k . . . . . for k = some constant
The recursive relation for a geometric function is of the form ...
S(n) = k·S(n-1) . . . . . . for k = some constant
The above recursive relation is not in either of these forms, so it is neither geometric nor arithmetic.
I have a similar problem here with a slightly different given.
Heights of men on a baseball team have a bell shaped distrubtion with a mean of 172cm and a standard deviation of 7cm. Using that is the empirical rule, what is the approximate percentage of the men between the following values?
a) 165 cm and 179cm
<span>b) 151cm and 193cm
</span>
The solution is:
<span>a. (165-172)/7 = -1, (179-172)/7 = 1, % by empirical rule = 68%
b. (151-172)/7 = -3, (193-172)/7 = 3, % by empirical rule = 99.7%
</span>
I hope that by examining the solution for this problem, it could help you answer your problem on your own.
Answer:
7326 is the answer
Step-by-step explanation:
222x33
Answer:
Step-by-step explanation:
to find unit rate, divide the denominator with the numerator in a way that the denominator becomes
Radioactive Decay Calculator: Complex Fracti
Multiplying Exponents Calculator: Greater Than
Frequency Distribution Calculator: (1/4) × (2/2) = (1 × 2) / (4 × 2) = 2/8
(1/4) × (4/4) = (1 × 4) / (4 × 4) = 4/16 (1/4) × (3/3) = (1 × 3) / (4 × 3) = 3/12
9514 1404 393
Answer:
A) 1.3×10^37 ergs
B) 1.435×10^3 mm
Step-by-step explanation:
A) The quantity is found by multiplying the rate by the time:
(3.9×10^33 ergs/s)×(3.25×10^3 s) = 1.2675×10^37 ergs ≈ 1.3×10^37 ergs
The least-precise contributor to the calculation has 2 significant digits, so we need to round the result to 2 significant digits.
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B) A fine human hair is more than 40×10^-3 mm in diameter, so the distance 1.435×10^-3 mm is completely unreasonable for railroad track spacing. The space between rails is closer to 1.4 meters. So 1.435×10^3 mm is a better measurement.