What is the area of a parallelogram whose vertices are A(−12, 2) , B(6, 2) , C(−2, −3) , and D(−20, −3) ?
1 answer:
To solve this, we simply have to get the length and the width. Based from the graph, we can see that the length is connected by 2 points (-12, 2) and (6, 2) or (-20, -3) and (-2, -3). The height between the two lengths is 5 which can be counted manually.
We use the distance formula to calculate the length from either pair of points.
length^2 = [(-12 – 6)^2 + (2 – 2)^2]
length = 18
Therefore the area is:
Area = length * height
Area = 18 * 5
Area = 90
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Answer:
y-coordinate = 0
Step-by-step explanation:
Consider the below diagram attached with this question.
Section formula:
If a point divides a line segment in m:n whose end points are and
, then the coordinates of that point are
From the below graph it is clear that the coordinates of end points are J(1,-10) and K(7,2). A point divides the line JK is 5:1.
Using section formula, the coordinates of that point are
Therefore, the y-coordinate of the point that divides the directed line segment from J to k into a ratio of 5:1 is 0.
