What is the area of a parallelogram whose vertices are A(−12, 2) , B(6, 2) , C(−2, −3) , and D(−20, −3) ?
1 answer:
To solve this, we simply have to get the length and the width. Based from the graph, we can see that the length is connected by 2 points (-12, 2) and (6, 2) or (-20, -3) and (-2, -3). The height between the two lengths is 5 which can be counted manually.
We use the distance formula to calculate the length from either pair of points.
length^2 = [(-12 – 6)^2 + (2 – 2)^2]
length = 18
Therefore the area is:
Area = length * height
Area = 18 * 5
Area = 90
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<h2>False.</h2>Step-by-step explanation:
A inscribe circle in a triangle means to draw the biggest circle possible inside such triangle. To do that perfectly, we first have to find the incenter of the circle, which is the intersection of all three internal bisector of the triangle, that point is the center of the inscribed circle.
Therefore, the statement is false.
In addition, a circumcenter allow to perfectly draw a circumscribed circle, which is outside the triangle, which is not the case here.
An image showing the inscribed circle is attached.
