Explanation: If a pyramid and a prism have the same base and height, their volumes are always in the ratio of 1:3 . As volume of prism is 108 cubic meters, volume of pyramid is 13×108=36 cubic meters.
Answer:
49.7%
Step-by-step explanation:
A cdircle is located within a square.
<u>Area of the circle</u>
Area = 
, where r = 4 units.
Area Circle = 50.3 units^2
<u>Area of the square</u>
Area = l*w or l^2 for a square, since l = w
Area = (10 units)^2
Area = 100 units^2
<u>Area in the square but outside the circle</u>
This is the difference [Square minus Circle Areas]
Square minus Circle Areas = 100 - 50.3 or <u>49.7 units^2</u>
<u>Probability</u>
The probability of picking a point in the square that is not in the circle is the ration of the two areas: <u>[Outside Circle/Square]x100%</u>
<u></u>
<u>(</u>49.7 units^2)/(100 units^2)x100% = 49.7%
<u></u>
Answer:
Part 1) 
Part 2) 
Part 3) 
Step-by-step explanation:
step 1
Find the measure of length side FG
In the right triangle EFG
we know that
----> by SOH (opposite side divided by the hypotenuse)
substitute the given values


step 2
Find the measure of length side EF
In the right triangle EFG
we know that
----> by CAH (adjacent side divided by the hypotenuse)
substitute the given values


step 3
Find the measure of angle G
we know that
---> by complementary angles in a right triangle

First add like terms in this case 1+7=8. Then then divide. 2x/8= 4. X=4
Solution: The given equation is →3 x+ 5 x=10
As you can see in the above equation on left side of equation the two terms are variables and on right side of equation the term is a constant term.Also you can see there is an operation called addition between the two variables on left side of equation.
In option (A), there is only a single term on right as well as left,so this can't be true.
In option (B), there is a constant and variable on left side of equation.So this is also untrue.
In option (C), variable being divided by numerator, so this is also untrue.
Option (D)3 x - 2 x = 10, is surely correct , because there are two variables on left side of equation and one constant on right side of equation, and there is an operation called subtraction between them .