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lesantik [10]
3 years ago
5

Suppose C and D represent two different school populations where C > D and C and D must be greater than 0. Which of the follo

wing expressions is the largest? Explain why. Show all work necessary. A: (C + D)2 B: 2(C + D) C: C2 + D2 D: C2 − D2
Mathematics
2 answers:
Snezhnost [94]3 years ago
7 0
The question or the problem wants to choose among the following expression is the largest, base on the data presented in the problem, the possible answer among the following choices is C2+D2.  I hope this helps :D
lakkis [162]3 years ago
4 0

Answer:

A.

Step-by-step explanation:

We have that C>0, D>o and C > D. Now,

A. (C+D)^2= C^2+2CD+D^2

B. 2(C+D) = 2C+2D

C. C^2+D^2

D. C^2-D^2

We have that C^2+2CD+D^2> C^2+D^2 (beacuse on left we have adding one extra positive term) and also C^2+D^2> C^2-D^2 (adding two positive values is greater than subtract two positive values), then

C^2+2CD+D^2> C^2-D^2

also, C^2+2CD+D^2> 2C+2D (also because the middle term). Then, the largest term is  (C+D)^2= C^2+2CD+D^2.

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A mountain climber ascends hundred feet per hour from his original position. after six hours is fine opposition is 11,600 feet a
Evgen [1.6K]

Answer:

Original position =6,800 feet.

800 (ft per hour) x 6(hours) =4800 ft

11,600-4,800=6,800 feet

Step-by-step explanation:

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3 years ago
What is the area of a semicircle with the diameter of 16
skelet666 [1.2K]

Answer:

50.265448

Step-by-step explanation:

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3 years ago
If J = 40° and G = 60°, then HJ _____ GJ
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Answer: A picture of the graph would help a ton but I'm pretty sure its "<"

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Read 2 more answers
A wide receiver catches a ball and begins to run for the endzone following a path defined by . A defensive player chases the rec
postnew [5]

Answer:

Receiver path:

x-5 = t(0)

y-50 = -10t

defender path:

x-10 = -0.9t

y-54 =-10.72t

Yes, he will reach the goal line (y = 0) before the defensive player catches him.

Step-by-step explanation:

Vector equation: (x-x1, y-y1) = t(a1, a2)

Horizontal component : x-x1= ta1

Vertical component: y-y1= ta2

(x-5, y-50) = t(0, -10)

x-5 = t(0)

y-50 =t(-10)

Parametric equation for the receiver path:

x-5 = t(0)

y-50 = -10t

(x - 10, y - 54) = t(-0.9, -10.72)

x - 10 = t(-0.9)

y - 54 = t(-10.72)

Parametric equation for the defender path:

x-10 = -0.9t

y-54 =-10.72t

At the 50yard line, using the receiver parametric equation for vertical component:

y-50 = -10t

At y= 50

50-50 = -10t

0= -10t

t= 0/-10 = 0

At y= 0

0-50 = -10t

t = -50/-10 = 5

Defender at y = 50

y-54 =-10.72t

50-54 =-10.72t

t = -4/-10.72 = 0.37

at y = 0

0-54 =-10.72t

t = -54/-10.72 = 5.04

t of receiver < t of defender

Since time of receiver at y=0 is less than time of defender, he will reach the goal line (y = 0) before the defensive player catches him.

3 0
3 years ago
What is the answer to 41x72.94
Alex Ar [27]

Answer:

2990.54

Step-by-step explanation:

The answer would be 2990.54.

3 0
3 years ago
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