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3 years ago

What specific measure of a geometric figure is shown in the image?

Mathematics

2 answers:

olga_2 [115]3 years ago

7 0

It’s A because the image shows that it’s between 30 and 40 therefore it’s 35 ! Hopefully this helped you : ] !!

Assoli18 [71]3 years ago

4 0

Answer:

The correct answer is 35 ° angle

You might be interested in

What is the probability

gulaghasi [49]

Answer: Last Option

$P=0.4125$

Step-by-step explanation:

In this case we have a uniform probability. In the graph the horizontal axis represents the possible values of the variable x and the vertical axis represents the probability P(x).

To calculate the probability that x is between 4.71 and 7.4 we calculate the area under the curve.

The horizontal length between 4.71 and 7.4 is:

$7.4-4.1 = 3.3$ .

Then notice that the vertical length in this interval is 0.125.

Then the area of a rectangle is:

$A = lw$

Where l is the length and w is the width.

In this case we have to:

$l = 3.3$

$w = 0.125$

$P = A = 3.3 * 0.125$

$P=0.4125$

3 0

3 years ago

Suppose that you had the following data set. 500 200 250 275 300 Suppose that the value 500 was a typo, and it was suppose to be

hodyreva [135]

Answer:

$\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305$

$s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108$

$\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105$

$s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221$

The absolute difference is:

$Abs = |340.221-115.108|= 225.113$

If we find the % of change respect the before case we have this:

$\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%$

So then is a big change.

Step-by-step explanation:

The subindex B is for the before case and the subindex A is for the after case

Before case (with 500)

For this case we have the following dataset:

500 200 250 275 300

We can calculate the mean with the following formula:

$\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305$

And the sample deviation with the following formula:

$s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108$

After case (With -500 instead of 500)

For this case we have the following dataset:

-500 200 250 275 300

We can calculate the mean with the following formula:

$\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105$

And the sample deviation with the following formula:

$s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221$

And as we can see we have a significant change between the two values for the two cases.

The absolute difference is:

$Abs = |340.221-115.108|= 225.113$

If we find the % of change respect the before case we have this:

$\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%$

So then is a big change.

8 0

3 years ago

URGENT PLEASE ANSWER!

zheka24 [161]

Answer:

Step-by-step explanation:

$3x+7\\\\3\left(x+\dfrac{7}{3}\right)=(3)(x)+(\not3)\left(\dfrac{7}{\not3}\right)=3x+7\qquad\boxed{YES}\\_{\text{used the distributive property: a(b + c) = ab + ac}}\\\\x+x+x+5+1=(x+x+x)+(5+1)=3x+6\neq3x+7\qquad\boxed{NO}\\\\8x+3-5x+4=(8x-5x)+(3+4)=3x+7\qquad\boxed{YES}\\\\7x+3\neq3x+7\qquad\boxed{NO}$