Question

HELP QUICK I ONLY HAVE 1 CHANCE

Answer 1

Short Answer D
Remark
Thank you for trying to pose the question so clearly.

Givens
T = 71 times
5 being rolled = 11

Substitution and solution.
P(T) = 71/100
P(6) = 11/100
P(Both) = P(T) * P(6)
P(Both) = 71/100 * 11/100

P(both) = (71 * 11) / 10000
P(Both) = 781/10000

Answer 2

Answer:

$\frac{781}{10000}$

Step-by-step explanation:

Given :

Number on the Cube Number of Times Rolled:

1                                                10  

2                                                 8  

3                                                33  

4                                                29  

5                                                 11  

6                                                 9  

Heads                                       Tails

29                                                  71

Total number of times cube rolled = 100

Total number of coin rolled = 100

Number of times getting 5 on a cube = 11

Number of times getting tails = 71

Now probability of getting 5 on the number cube :

=$\frac{\text{Number of times 5 occurred on a cube}}{\text{Number of times cube is rolled}}$

 = $\frac{11}{100}$

Probability of getting tails = $\frac{\text{Number of times tails occurred on a coin}}{\text{Number of times coin is rolled}}$

                                         = $\frac{71}{100}$

Probability of rolling a 5 on the number cube and the coin landing on tails =  $\frac{11}{100} \times \frac{71}{100}$

        =  $\frac{781}{10000}$

Thus the probability of rolling a 5 on the number cube and the coin landing on tails is $\frac{781}{10000}$