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larisa [96]
3 years ago
7

HELP QUICK I ONLY HAVE 1 CHANCE

Mathematics
2 answers:
guajiro [1.7K]3 years ago
8 0
Short Answer D
Remark

Thank you for trying to pose the question so clearly.

Givens
T = 71 times
5 being rolled = 11

Substitution and solution.
P(T) = 71/100
P(6) = 11/100
P(Both) = P(T) * P(6)
P(Both) = 71/100 * 11/100

P(both) = (71 * 11) / 10000
P(Both) = 781/10000
brilliants [131]3 years ago
3 0

Answer:

\frac{781}{10000}

Step-by-step explanation:

Given :

Number on the Cube Number of Times Rolled:

1                                                10  

2                                                 8  

3                                                33  

4                                                29  

5                                                 11  

6                                                 9  

Heads                                       Tails

29                                                  71

Total number of times cube rolled = 100

Total number of coin rolled = 100

Number of times getting 5 on a cube = 11

Number of times getting tails = 71

Now probability of getting 5 on the number cube :

=\frac{\text{Number of times 5 occurred on a cube}}{\text{Number of times cube is rolled}}

 = \frac{11}{100}

Probability of getting tails = \frac{\text{Number of times tails occurred on a coin}}{\text{Number of times coin is rolled}}

                                         = \frac{71}{100}

Probability of rolling a 5 on the number cube and the coin landing on tails =  \frac{11}{100} \times \frac{71}{100}

        =  \frac{781}{10000}

Thus the probability of rolling a 5 on the number cube and the coin landing on tails is \frac{781}{10000}                                                                                  

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