The amount of water that is needed to fill the pool is equal to the volume of the pool.

The pool is rectangular, with uniform depth so the volume of pool will be the product of its length , width and depth.

Thus,

Volume = 25 x 18 x 6 = 2700 ft³

This means, 2700 ft³ water is needed to fill the pool.

8 0

2 years ago

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(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2

Montano1993 [528]

Answer:

$\dfrac{m^3}{16p^2q^2}$

Step-by-step explanation:

Given:

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}$

$m^{-1}=\dfrac{1}{m}$

$q^0=1$

$2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}$

$(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}$

$m^{-1}=\dfrac{1}{m}$

$2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}$

$\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}$

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}$

8 0

3 years ago

ASAP I NEED HELP PLZ PLZ PLZ PLZ

liberstina [14]

Answer: 64 ................ :)

Step-by-step explanation:

3 0

3 years ago

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Order the following integers from least to greatest.-41, -53, -73, -78 A. -78, -53, -73, -41 B. -78, -73, -41, -53 C. -73, -78,

irakobra [83]

The value of negative integers decreases the further we get from the 0 point on the number line.

Therefore, if we arrange the numbers in ascending order ignoring the negative sign, the numbers will be in descending order when the negative sign is included.

By the definition above, we can say that the smallest number of the lot is -78 and the largest one is -41.

The numbers can be ordered from least to greatest as shown below:

$-78,-73,-53,-41$

OPTION D is the correct answer.

3 0

1 year ago