If the two triangles are similar, then the corresponding parts of congruent triangles are congruent.

That means that the length of RQ is the same as the corresponding side from triangle ABC.

Hope this helps :)

4 0

3 years ago

Find the quotient. Write your answer in standard form. : 3-i/3+i

s344n2d4d5 [400]

The answer is C. 4/5 - 3/5 i

$\frac{3-i}{3+i} = \frac{(3-i)(3-i)}{(3+i)(3-i)} \\ \\ 
(a+b)(a-b) = a^{2} -b^{2} \\ \\ 
\frac{(3-i)(3-i)}{(3+i)(3-i)}= \frac{ (3-i)^{2} }{3^{2}-i^{2} } \\ \\ 
(a-b)^{2} =a^{2}-2ab+b^{2} \\ \\ 
 \frac{ (3-i)^{2} }{3^{2}-i^{2} } = \frac{3^{2}-2*3*i+i^{2} }{3^{2}-i^{2} } = \frac{9-6i+i^{2}}{9-i^{2}} \\ \\ 
i = \sqrt{-1} \\ i^{2}=-1 \\ \\ 
\frac{9-6i+i^{2}}{9-i^{2}} = \frac{9-6i-1}{9+1} = \frac{8-6i}{10}= \frac{8}{10}- \frac{6i}{10}= \frac{4}{5}- \frac{3}{5}i$

8 0

3 years ago