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balu736 [363]
3 years ago
5

Please halp. i am not smart

Mathematics
1 answer:
Leya [2.2K]3 years ago
6 0

Let's start with 22-C!

To figure out the problem, let's establish what it's asking. It wants to know the one time fee of using the trash dumpster. Your teacher may have taught you a better way to do this, but I'll show you how to solve it via logic.

We first need to set up a basic equation. X will be the unknown fee, 195 will act as the total, and 9(15) will represent the remaining cash (you get this from 15$ an hour for 9 hours).

The equation should look something like this:

x + 9(15) = 195 OR (simplified) x + 135 = 195.

At this point we can solve it like a regular equation. Subtract 135 on both sides:

x = 60. Therefore, the fee for using the dumpster is 60$.

Now we can move on to 23-A & B!

First, let's go over 2 basics: point slope formula and slope intercept.

Point slope formula: <em>y - yy-y_{1} = m(x - x_{1} )</em>

Slope intercept: <em>y = mx + b</em>

We know that .5 is the slope because it's dependent on an amount of time (or dependent in general). 64 can be used as y1 and 48 as x1.

The formula would be: y - 64 = .5(x - 48).

As for part B, we plug in the same numbers! We've previously found that .5 is the slope (m) and it appears you already know that the y-intercept (b) is 40. Plug it in like so:

y = .5x + 40

All of the answers are bolded, I hope this helped!

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A company manager for a tire manufacturer is in charge of making sure there is the least amount of defective tires. If the tire
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For a standard normal distribution, (with mean 0 and standard deviation 1), the lower and upper quartiles are located at -0.67448 and +0.67448 respectively. Thus the interquartile range (IQR) is 1.34896.

And the manager decides to reject a tire as underweight if it falls more than 1.5 interquartile ranges below the lower quartile of the specified shipment of tires.

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The proportion of tires that will fall 1.5 of the interquartile range below the lower quartile = P(x < -2.69792) ≈ P(x < -2.70)

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P(x < -2.70) = 0.00347 = 0.347% of the total tires will be rejected as underweight

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