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KIM [24]
3 years ago
14

Brent has two barcode printing machines. Each machine can print 25 barcodes per minute. On day 1, only the first machine was use

d, and it printed 95 barcodes. On the following day, the first machine printed for x minutes and the second machine printed for y minutes. Which expression shows the total number of barcodes printed by both machines during these two days?
Mathematics
2 answers:
Sonja [21]3 years ago
8 0
I think it would be 95 + 25x + 25y
Serhud [2]3 years ago
8 0

Answer:

The total number of barcodes printed by both machines during these two days is given by T=95+25x+25y

Step-by-step explanation:

Given : Brent has two barcode printing machines. Each machine can print 25 barcodes per minute. On day 1, only the first machine was used, and it printed 95 barcodes. On the following day, the first machine printed for x minutes and the second machine printed for y minutes.  

To find : Which expression shows the total number of barcodes printed by both machines during these two days?        

Solution :

On day 1,

Only the first machine was used, and it printed 95 barcodes.  

So, On 1 day the number of barcodes print = 95      

On day 2,

The first machine printed for x minutes and the second machine printed for y minutes.  

We have given that, Each machine can print 25 barcodes per minute.

In x minutes it print 25x barcodes.

In y minutes it print 25y barcodes.

So, On 2 day the number of barcodes print is 25x+25y

The total number of barcodes printed by both machines during these two days is given by T=95+25x+25y

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<u><em>Answer:</em></u>

Part a .............> x = 11

Part b .............> k = 57.2

Part c .............> y = 9.2

<u><em>Explanation:</em></u>

The three problems deal with inverse variation between two variables

An inverse variation relation between two variables means that when one of the variables increases, the other will decrease (and vice versa)

<u>Mathematically, an inverse variation relation is represented as follows:</u>

y = \frac{k}{x}

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<u><em>Now, let's check the givens:</em></u>

<u>Part a:</u>

We are given that y = 3 and k = 33

<u>Substitute in the original relation and solve for x as follows:</u>

y = \frac{k}{x}\\ \\3 = \frac{33}{x}\\ \\x=\frac{33}{3}=11

<u>Part b:</u>

We are given that y = 11 and x = 5.2

<u>Substitute in the original relation and solve for k as follows:</u>

y=\frac{k}{x}\\ \\11=\frac{k}{5.2}\\ \\k=11*5.2=57.2

<u>Part c:</u>

We are given that x=7.8 and k=72

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y=\frac{k}{x}=\frac{72}{7.8}=9.2 to the nearest tenth

Hope this helps :)

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