Answer: No solutions
If i put any combo of horses of single or odd, always an even number at last stall.
Answer:
Minimum: 50
Lower Quartile: 59
Median: 66
Upper Quartile: 74
Maximum: 92
Step-by-step explanation:
50, 55, 58, 60, 62, 64, 68, 70, 72, 76, 84, 92
Minimum: 50
Lower Quartile: (58 + 60)/2 = 59
Median: (64 + 68)/2 = 66
Upper Quartile: (72 + 76)/2 = 74
Maximum: 92
Answer:
The answer is -5, -4, -3, -2, -1, 0, 1.
Step-by-step explanation:
Because they are behind the number 2
-2(x + 3) = -2(x + 1)
-2x - 6 = -2x - 2
-2x + 2x = -2 + 6
0 = 4
Therefore, the system has no solution.
Answer:
x=7
y=-1
Step-by-step explanation:
When the two equations are solved together, they form simultaneous equations.
x+y=6
x-y=8
Let us use the elimination method. if we add the two equations, we eliminate y.
2x=14
x=7
Let us substitute for the value of x obtained above.
x-y=8
7-y=8
y=7-8
y=-1