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Ilya [14]
4 years ago
11

Is 21, 28,35 the sides of a right triangle?

Mathematics
1 answer:
olga_2 [115]4 years ago
5 0

Answer:

yes

Step-by-step explanation:

divide each by 7 =

21/7 = 3

28/7 =4

35/7 = 5

3,4,5 are always a perfect triple, and multiples of 345 are perfect triples as well. Therefore, they are sides of a right triangle.

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I need homework help! Its proportions, but the thing is, I'm terrible at them. All I know is that is/of=x/100.
masha68 [24]
19)  15/a = 3/2 

Start by cross multiplying....

3a = 30 

Divide both sides 3 

a = 10 

21)   2/7 = 4/d 

        2d = 28
       
        d= 14 

23)  8/p = 3/10

       
80 = 3p
         p = 26.66

25)  2 / -5 = 6/t
        2t = -30

      t = -15


7 0
3 years ago
A board game has a spinner divided into sections of equal size. Each section is labeled with a number between 1 and 5. Which num
Valentin [98]

Answer:

75

Step-by-step explanation:

first, there are three 5's on the spinner, with a total of 12 sections. 3/12 = 0.25, so you multiply 0.25 times 300 (the total spins) and get 75

3 0
3 years ago
Two lengths are in ratio 7:8.if the first length is 273. What amount is the second length
Sergio [31]

Answer:

312

Step-by-step explanation:

Since the ratio is 7:8, mark it as 7x:8x.

Now, they said that the first length is 273. Solve the equation:

7x=273

x=39

Substitute it into 8x. 39*8=312. That's your answer.

PLS MARK BRANILIEST!!!

3 0
3 years ago
Work out the area of abcd.<br><br> please ensure you give workings out too.
ipn [44]

Answer:

\displaystyle A_{\text{Total}}\approx45.0861\approx45.1

Step-by-step explanation:

We can use the trigonometric formula for the area of a triangle:

\displaystyle A=\frac{1}{2}ab\sin(C)

Where a and b are the side lengths, and C is the angle <em>between</em> the two side lengths.

As demonstrated by the line, ABCD is the sum of the areas of two triangles: a right triangle ABD and a scalene triangle CDB.

We will determine the area of each triangle individually and then sum their values.

Right Triangle ABD:

We can use the above area formula if we know the angle between two sides.

Looking at our triangle, we know that ∠ADB is 55 DB is 10.

So, if we can find AD, we can apply the formula.

Notice that AD is the adjacent side to ∠ADB. Also, DB is the hypotenuse.

Since this is a right triangle, we can utilize the trig ratios.

In this case, we will use cosine. Remember that cosine is the ratio of the adjacent side to the hypotenuse.

Therefore:

\displaystyle \cos(55)=\frac{AD}{10}

Solve for AD:

AD=10\cos(55)

Now, we can use the formula. We have:

\displaystyle A=\frac{1}{2}ab\sin(C)

Substituting AD for a, 10 for b, and 55 for C, we get:

\displaystyle A=\frac{1}{2}(10\cos(55))(10)\sin(55)

Simplify. Therefore, the area of the right triangle is:

A=50\cos(55)\sin(55)

We will not evaluate this, as we do not want inaccuracies in our final answer.

Scalene Triangle CDB:

We will use the same tactic as above.

We see that if we can determine CD, we can use our area formula.

First, we can determine ∠C. Since the interior angles sum to 180 in a triangle, this means that:

\begin{aligned}m \angle C+44+38&=180 \\m\angle C+82&=180 \\ m\angle C&=98\end{aligned}

Notice that we know the angle opposite to CD.

And, ∠C is opposite to BD, which measures 10.

Therefore, we can use the Law of Sines to determine CD:

\displaystyle \frac{\sin(A)}{a}=\frac{\sin(B)}{b}

Where A and B are the angles opposite to its respective sides.

So, we can substitute 98 for A, 10 for a, 38 for B, and CD for b. Therefore:

\displaystyle \frac{\sin(98)}{10}=\frac{\sin(38)}{CD}

Solve for CD. Cross-multiply:

CD\sin(98)=10\sin(38)

Divide both sides by sin(98). Hence:

\displaystyle CD=\frac{10\sin(38)}{\sin(98)}

Therefore, we can now use our area formula:

\displaystyle A=\frac{1}{2}ab\sin(C)

We will substitute 10 for a, CD for b, and 44 for C. Hence:

\displaystyle A=\frac{1}{2}(10)(\frac{10\sin(38)}{\sin(98)})\sin(44)

Simplify. So, the area of the scalene triangle is:

\displaystyle A=\frac{50\sin(38)\sin(44)}{\sin(98)}

Therefore, our total area will be given by:

\displaystyle A_{\text{Total}}=50\cos(55)\sin(55)+\frac{50\sin(38)\sin(44)}{\sin(98)}

Approximate. Use a calculator. Thus:

\displaystyle A_{\text{Total}}\approx45.0861\approx45.1

8 0
3 years ago
Which ordered pairs are solutions to the inequality x+3y≥−8?
crimeas [40]
(-6,0)
(-1,-2)
(-5,-1)
4 0
3 years ago
Read 2 more answers
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