How to do this problem
1 answer:
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Answer:
The value of x would be or
Step-by-step explanation:
Given,
x tons of 10% gravel G mixture is mixed with y ton of 2% gravel G to obtain 5% gravel mixture,
Thus, gravel G in x ton + gravel in y ton = gravel G in the resultant mixture,
⇒ 0.1x + 0.02y = 0.05(x+y),
0.1x - 0.05x = 0.05y - 0.02y
0.05x = 0.03y
Now, resultant mixture is z ton,
i.e.
From equation (1),
Answer:
The 't' test statistic = 1.46 < 1.69
The test of hypothesis is H 0 :μ = 800 is accepted
A sample of 30 bulbs are found came from average µ= 800
Step-by-step explanation:
Step 1:-
Given population of mean μ = 800
given size of small sample n =30
sample standard deviation 'S' = 45
Mean value of the sample χ = 788
Null hypothesis µ =800
alternative hypothesis µ ≠ 800
<u>Step 2</u>:-
The 't' test statistic t =
t = = 1.4607
<u>Step 3</u>:-
The degrees of freedom γ = n-1 = 30-1 =29
From "t" value from table at 0.05 level of significance ( t = 1.69)
The calculated value t = 1.4607 < 1.69
Therefore The null hypothesis H_{0} ' is accepted.
<u>conclusion</u>:-
A sample of 30 bulbs are came found from average µ= 800