Question

Need help pls someone

Answer 1

$\bf \boxed{-\sqrt{16a^4b^6}}\implies -\sqrt{4^2(a^2)^2(b^3)^2}\implies -4a^2b^3\implies \boxed{-4a^2|b^3|} \\\\\\ \boxed{\sqrt[3]{-16a^4b^7}}~~ \begin{cases} 16=2\cdot 2\cdot 2\cdot 2\\ \qquad 2^3\cdot 2\\ a^4=a^{3+1}\\ \qquad a^3a^1\\ b^7=b^{2\cdot 3+1}\\ \qquad (b^2)^3b^1 \end{cases}\implies \sqrt[3]{-2^3\cdot 2a^3a^1(b^2)^3b^1} \\\\\\ -2a(b^2)\sqrt[3]{2a^1b^1}\implies \boxed{-2ab^2\sqrt[3]{2ab}}$

$\bf \boxed{\sqrt[3]{16a^4b^6}}~~ \begin{cases} 16=2\cdot 2\cdot 2\cdot 2\\ \qquad 2^3\cdot 2\\ a^4=a^{3+1}\\ \qquad a^3a^1\\ b^6=b^{2\cdot 3}\\ \qquad (b^2)^3 \end{cases}\implies \sqrt[3]{2^3\cdot 2a^3a(b^2)^3} \\\\\\ \boxed{2ab^2\sqrt[3]{2a}}$

Answer 2

They are directly across from each other ._.