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blsea [12.9K]
3 years ago
11

An expression involves subtracting two numbers from a positive number. Under what circumstances with the value expression be neg

ative? give an example
Mathematics
1 answer:
Svetach [21]3 years ago
7 0
So (positive integer)-x-y can be negative
so to get a negative number as your result/answer, x+y must be greater than (positve integer) so  for example


lets say (positive integer)=8
x+y must be greater than 8 to make the equation negative so
example
x=5
y=4
x+y=9
8-9=-1
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Need help plz it’s only one question!!!
Semenov [28]
2.50 (5) = 12.5

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3 years ago
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Use Lagrange multipliers to find the maximum and minimum values of f(x,y)=x+4y subject to the constraint x2+y2=9, if such values
Vesnalui [34]

The Lagrangian is

L(x,y,\lambda)=x+4y+\lambda(x^2+y^2-9)

with critical points where the partial derivatives vanish.

L_x=1+2\lambda x=0\implies x=-\dfrac1{2\lambda}

L_y=4+2\lambda y=0\implies y=-\dfrac2\lambda

L_\lambda=x^2+y^2-9=0

Substitute x,y into the last equation and solve for \lambda:

\left(-\dfrac1{2\lambda}\right)^2+\left(-\dfrac2\lambda\right)^2=9\implies\lambda=\pm\dfrac{\sqrt{17}}6

Then we get two critical points,

(x,y)=\left(-\dfrac3{\sqrt{17}},-\dfrac{12}{\sqrt{17}}\right)\text{ and }(x,y)=\left(\dfrac3{\sqrt{17}},\dfrac{12}{\sqrt{17}}\right)

We get an absolute maximum of 3\sqrt{17}\approx12.369 at the second point, and an absolute minimum of -3\sqrt{17}\approx-12.369 at the first point.

4 0
3 years ago
Renee is simplifying the expression (7) (StartFraction 13 over 29 EndFraction) (StartFraction 1 over 7 EndFraction). She recogni
dsp73

Answer:

The correct option is commutative property.

Step-by-step explanation:

The expression that Renee is simplifying is:

(7)\cdot(\frac{13}{29})\cdot(\frac{1}{7})

It is provided that, Renee recognizes that 7 and \frac{1}{7} are reciprocals, so she would like to find their product before she multiplies by \frac{13}{29}.

The associative property of multiplication states that:

a\times b\times c=(a\times b)\times c=a\times (b\times c)

The commutative property of multiplication states that:

a\times b\times c=a\times c\times b=c\times a\times b

The distributive property of multiplication states that:

a\cdot (b+c)=a\cdot b+a\cdot c

The identity property of multiplication states that:

a\times 1=a\\b\times 1=b

So, Renee should use the commutative property of multiplication to find the product of 7 and \frac{1}{7},

(7)\cdot(\frac{13}{29})\cdot(\frac{1}{7})=(7\times\frac{1}{7})\times\frac{13}{29}=\frac{13}{29}

Thus, the correct option is commutative property.

5 0
3 years ago
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Write the trigonometric expression <br> Cos (arcsin (u))<br> As an algebraic expression in u
makvit [3.9K]
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We can use Pythagorean Theorem to find the adjacent (x value).

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Cosine is adjacent over hypotenuse.

So our answer is sqrt(1-u^2)/1

Or just sqrt(1-u^2)







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3 years ago
What is the solution of 5 = t/2 -3?
Sladkaya [172]

Answer:

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you have to change the numbers to get just the variable.

we start from -3.

5=t/2-3

8=t/2

(we multiply by 2 instead of dividing)

8×2=16

t=16

5 0
3 years ago
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