Answer:
It will be 0.2
Step-by-step explanation:
Hope this Helped
Answer: 20
Explanation: Alright, so basically you’re going to want to use PEMDAS (Parenthesis, Exponents, Multiplication/ Division, Addition/ Subtraction)
* just means multiply.. sooo the problem looks like this:
6x(12-7.5)-7
We’ll start at the parentheses :)
So (12-7.5) = 4.5
Now our problem looks like: 6x(4.5)-7
Following PEMDAS, the next thing to come up is multiplication! So we’re going to multiply 6 by 4.5 ...
6x4.5=27
After this our problem looks like: 27-7
So now it’s just simple math...
27-7= 20
The question is an illustration of composite functions.
- Functions c(n) and h(n) are
and 
- The composite function c(n(h)) is

- The value of c(n(100)) is

- The interpretation is: <em>"the cost of working for 100 hours is $130000"</em>
The given parameters are:
- $5000 in fixed costs plus an additional $250
- 5 systems in one hour of production
<u>(a) Functions c(n) and n(h)</u>
Let the number of system be n, and h be the number of hours
So, the cost function (c(n)) is:

This gives


The function for number of systems is:


<u>(b) Function c(n(h))</u>
In (a), we have:


Substitute n(h) for n in 

Substitute 


<u>(c) Find c(n(100))</u>
c(n(100)) means that h = 100.
So, we have:



<u>(d) Interpret (c)</u>
In (c), we have: 
It means that:
The cost of working for 100 hours is $130000
Read more about composite functions at:
brainly.com/question/10830110
Answer:

Step-by-step explanation:
1.
Simplify the expression by combining like terms. Remember, like terms have the same variable part, to simplify these terms, one performs operations between the coefficients. Please note that a variable with an exponent is not the same as a variable without the exponent. A term with no variable part is referred to as a constant, constants are like terms.



2.
Use a very similar method to solve this problem as used in the first. Please note that all of the rules mentioned in the first problem also apply to this problem; for that matter, the rules mentioned in the first problem generally apply to any pre-algebra problem.



3.
Use the same rules as applied in the first problem. Also, keep the distributive property in mind. In simple terms, the distributive property states the following (
). Also note, a term raised to an exponent is equal to the term times itself the number of times the exponent indicates. In the event that the term raised to an exponent is a constant, one can simplify it. Apply these properties here,







4.
The same method used to solve problem (3) can be applied to this problem.





