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Tema [17]
3 years ago
13

a football team gained 9 yards on one play and then lost 22 yards on the next. Write a sum of integers to find the overall chang

e in Field position.
Mathematics
1 answer:
raketka [301]3 years ago
8 0
If\ they\ gained\ 9\ yards\ it\ as\ in\ our\ sum\ positive\ number\\\\If\ they\ lost\ 22\ yards\ it\ is\ negative\ number\ in\ our\ sum\\so\\9-22=-13\\\\Their\ overall\ lost\ was\ 13\ yards.\\\\Their\ position\ changed\ by\ 13\ yards\ negatively.(they\ go\ back)
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How would I solve (-2-2i)(-4-3i)(7+8)
siniylev [52]
(-2-2i)(-4-3i)(7+8)=\\
15(-2-2i)(-4-3i)=\\
15(8+6i+8i-6)=\\
15(2+14i)=\\
30+210i
5 0
3 years ago
Car X weighs 136 pounds more than car Z. Car Y weighs 117 pounds more than car Z. The total weight of all three cars is 9439 pou
Aleksandr [31]

Let x, y and z denote the weighs of car X, car Y and car Z, respectively.

We know that car X weighs 136 more than car Z, this can be express by the equation:

x=z+136

We also know that Y weighs 117 pounds more than car Z, this can be express as:

y=z+117

Finally, we know that the total weight of all the cars is 9439, then we have:

x+y+z=9439

Hence, we have the system of the equations:

\begin{gathered} x=z+136 \\ y=z+117 \\ z+y+z=9439 \end{gathered}

To solve the system we can plug the values of x and y, given in the first two equations, in the last equation; then we have:

\begin{gathered} z+136+z+117+z=9439 \\ 3z=9439-136-117 \\ 3z=9186 \\ z=\frac{9186}{3} \\ z=3062 \end{gathered}

Now that we have the value of z we plug it in the first two equations to find x and y:

\begin{gathered} x=3062+136=3198 \\ y=3062+117=3179 \end{gathered}

Therefore, car X weighs 3198 pound, car Y weighs 3179 pounds and car Z weighs 3062 pounds.

4 0
1 year ago
I'm confused how to solve this, can someone help??
frutty [35]
Add one on both sides of the equation. You would end up with -6=x/3. You would then cross multiply, so -6 times 3 and 1 (the denominator for -6) times x and you would get -18=x
6 0
3 years ago
Read 2 more answers
I need some help on this question. Segment LM is the midsegment of trapezoid ABCD. AB=48, and DC=88. What is LM? I am not sure h
agasfer [191]
AB=48, DC=88

48+88=136
136÷2=68

Answer: LM=68
Remember that the length of the mid segment in a trapezoid is half the sum of the base lengths.
4 0
3 years ago
The gross weight of a package and its contents is 11 pounds 5 ounces. If the packaging weighs 1 pound 15 ounces, what's the net
dsp73
Answer A
For ease convert both into ounces.

Gross = (11x16) + 5 = 181 ounces
Packaging = (1x16) + 15 = 31 oz.

Now subtract Packaging from Gross

181 - 31 = 150 oz.

Divide by 16 to get pounds

150/16 = 9.375 - hence 9 lb.

and multiply 16 by .375 for ounces

0.375 x 16 = 6 oz.

Thus A : 9lb 6 oz
5 0
3 years ago
Read 2 more answers
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