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3 years ago

Solve log 2x + log 5 = 1. Round to the nearest thousandth if necessary.

Mathematics

1 answer:

Aloiza [94]3 years ago

4 0

I think that 0.015 is the answer?

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At a certain zoo, the average mass of one blue whale is measured to be 1.9 × 105

professor190 [17]

Answer:

2.7930 × $10^{4}$

Step-by-step explanation:

1.9 × 105 × 140 = 27,930

Scientific notation: 2.7930 × $10^{4}$

3 0

2 years ago

A nearby pool holds 30,000 gallons. The pool has been filled with 19,500 gallons of water. If the variable w stands for the amou

Nataly_w [17]

30,000 - 19,500 = 10,500 gallons left to fill the pool. So I am assuming the answer would be w = 10,500 gallons... unless there was an equation missing in the question

4 0

3 years ago

At a display booth at an amusement park, every visitor gets a gift bag. Some

kotegsom [21]

The bag will often contain all three items every 70 bags ⇒ answer C

Step-by-step explanation:

At a display booth at an amusement park, every visitor gets a gift bag

according to these information:

1. Hat Every 2nd visitor

2. T-shirt Every 7th visitor

3. Backpack Every 10th visitor

We need to know how often a bag will contain all three items

To solve this problem you must find a number divisible by 2, 7, and 10

To find that number start with the multiples of the largest one and

check them with the other two numbers

∵ The largest number is 10

∵ The multiples of 10 are 10 , 20 , 30 , 40 , 50 , 60 , 70 , 80 , .......

- Look for the first multiple of 10 is divisible by 7

∵ 70 is the first multiple of 10 divisible by 7

∵ 70 is divisible by 2 because its even number

∴ 70 is the smallest number divisible by 2, 7 and 10

The bag will often contain all three items every 70 bags

Learn more:

You can learn more about numbers in brainly.com/question/537998

#LearnwithBrainly

4 0

3 years ago

There are five identical blue books, two identical green books, and three identical black books. How many different patterns can

dsp73

Answer:

2520 patterns

Step-by-step explanation:

In 'n' 10! ways, books can be arranged. But, there are also 5! permutation of blue books 'n1', 2! permutation of identical green books 'n2', and 3! permutation identical black books 'n3'.

Therefore, for non identical arrangements:

$\frac{n!}{n1!n2!n3!}$