3 years ago

Choose the best graph that represents the linear equation: X = -3

1 answer:

4 0

This is how the graph should look like

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Anarel [89]

The solution to this is 5√(11)/11

3 0

3 years ago

AlekseyPX

Both the numerator and denominator have a 9 and a "b" in common, so we can reduce the fraction to:

3c/4d

5 0

3 years ago

UkoKoshka [18]

Since the limit becomes the undetermined form

$\displaystyle \lim_{x\to 1} \dfrac{x^3-2x^2+3x-2}{2x^4-3x+1} \to \dfrac{0}{0}$

it means that both polynomials have a root at $x=1$ . So, we can fact both numerator and denominator:

$x^3-2x^2+3x-2 = (x-1)(x^2-x+2)$

$2x^4-3x+1 = (x-1)(2x^3+2x^2+2x-1)$

So, the fraction becomes

$\dfrac{(x-1)(x^2-x+2)}{(x-1)(2x^3+2x^2+2x-1)} = \dfrac{x^2-x+2}{2x^3+2x^2+2x-1}$

Now, as x approaches 1, you have no problems anymore:

$\displaystyle \lim_{x\to 1} \dfrac{x^2-x+2}{2x^3+2x^2+2x-1} \to \dfrac{2}{5}$

4 0

3 years ago

defon

Answer:

A&B

Step-by-step explanation:

8 0

2 years ago

Agata [3.3K]

Answer:

h(t) = 16t changes 16 units every t. in the interval t=7 to t=2,

if its asking for:

$\int\limits^2_7 {16t} \, dt$

then it's

16(2) - 16(7) = 32 - 112 = -80

4 0

3 years ago