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3 years ago

What is the standard form of Y=2/5x+2

Mathematics

1 answer:

Troyanec [42]3 years ago

7 0

bearing in mind that standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

$\bf y = \cfrac{2}{5}x+2\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{5}}{5(y)=5\left( \cfrac{2}{5}x+2 \right)}\implies 5y=2x+10 \\\\\\ -2x+5y=10\implies 2x-5y=-10$

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How to solve 1-(-8)- 12/-3

Fudgin [204]

Answer:

ok so the answer is 13

Step-by-step explanation:

to solve you..

PEMDAS

PLEASE EXUSE MY DEAR AUNT SALLY

1-(-8)-12/-3

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3 years ago

For t=2, 15t - 2t is equal to

weqwewe [10]

Answer:

Step-by-step explanation:

=15(2) - 2(2)

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3 years ago

A soda bottling company’s manufacturing process is calibrated so that 99% of bottles are filled to within specifications, while

bija089 [108]

Answer:

The probability that the assembly line will be shut down is 0.00617.

Step-by-step explanation:

We are given that a soda bottling company’s manufacturing process is calibrated so that 99% of bottles are filled to within specifications, while 1% is not within specification.

Every hour, 12 random bottles are taken from the assembly line and tested. If 2 or more bottles in the sample are not within specification, the assembly line is shut down for recalibration.

Let X = Number of bottles in the sample that are not within specification.

The above situation can be represented through binomial distribution;

$P(X=r)=\binom{n}{r} \times p^{r}\times (1-p)^{n-r};x=0,1,2,3,.....$

where, n = number of trials (samples) taken = 12 bottles

x = number of success = 2 or more bottles

p = probabilitiy of success which in our question is probability that

bottles are not within specification, i.e. p = 0.01

So, X ~ Binom (n = 12, p = 0.01)

Now, the probability that the assembly line will be shut down is given by = P(X $\geq$ 2)

P(X $\geq$ 2) = 1 - P(X = 0) - P(X = 1)

= $1-\binom{12}{0} \times 0.01^{0}\times (1-0.01)^{12-0}-\binom{12}{1} \times 0.01^{1}\times (1-0.01)^{12-1}$

= $1-(1 \times 1\times 0.99^{12})-(12 \times 0.01^{1}\times 0.99^{11})$

= 0.00617

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