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3 years ago

What is the standard form of Y=2/5x+2

Mathematics

1 answer:

Troyanec [42]3 years ago

7 0

bearing in mind that standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

$\bf y = \cfrac{2}{5}x+2\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{5}}{5(y)=5\left( \cfrac{2}{5}x+2 \right)}\implies 5y=2x+10 \\\\\\ -2x+5y=10\implies 2x-5y=-10$

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miv72 [106K]

Answer:

9825

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

A rectangular photograph is nine centimeters wide and fourteen centimeters long. The photograph is enlarged by increasing the le

koban [17]

Answer:

Width=13cm

Length=18cm

Step-by-step explanation:

Width of the Initial Photograph=9cm

Length of the Initial Photograph=14cm

If width and length are increased by an equal amount, say x

New Width=9+x

New Length=14+x

Area of the new photo is 108 square centimeters greater than the area of the original photo.

Area of Original Photo=14*9=126cm²

Aeea of the New Photo=126+108=234cm²

Therefore:

(9+x)(14+x)=234

126+9x+14x+x²-234=0

x²+23x-108=0

x²+27x-4x-108=0

x(x+27)-4(x+27)=0

(x+27)(x-4)=0

x+27=0 or x-4=0

x=-27 or x=4

Since x≠-27

x=4cm

The dimensions of the new photo are:

Width=9+x=9+4=13cm

Length=14+x=14+4=18cm

4 0

3 years ago

The points P, Q, R and S all lie on the same line segment, in that order, such that the ratio of PQ : QR: RS is equal to 4:2:1.

Natasha2012 [34]

Answer:

PR = 12

Step-by-step explanation:

P-----------Q-----------R----------S

ratio

4:2:1

PS = 14

add the ration = 4 + 2 + 1 = 7

14 / 7 = 2

PQ at 4 x 2 = 8

QR at 2 x 2 = 4

RS at 1 x 2 = 2

------------

PR = PQ + QR

PR = 8 + 4

PR = 12

5 0

3 years ago

Read 2 more answers

Anyone can help me with this

Leokris [45]

Given:

The data values are

11, 12, 10, 7, 9, 18

To find:

The median, lowest value, greatest value, lower quartile, upper quartile, interquartile range.

Solution:

We have,

11, 12, 10, 7, 9, 18

Arrange the data values in ascending order.

7, 9, 10, 11, 12, 18

Divide the data in two equal parts.

(7, 9, 10), (11, 12, 18)

Divide each parenthesis in 2 equal parts.

(7), 9, (10), (11), 12, (18)

Now,

Median = $\dfrac{10+11}{2}$

= $\dfrac{21}{2}$

= $10.5$

Lowest value = 7

Greatest value = 18

Lower quartile = 9

Upper quartile = 12

Interquartile range (IQR) = Upper quartile - Lower quartile

= 12 - 9

= 3

Therefore, median is 10.5, lowest value is 7, greatest value is 18, lower quartile 9, upper quartile 12 and interquartile range is 3.

8 0

3 years ago

Please help me Im almost done

SSSSS [86.1K]

Answer:

$\mathsf {x = 76}$

Step-by-step explanation:

The given pair of angles lie on a line, hence they are classified as linear angles. They possess the property by which their sum is equal to 180°.

$\textsf {Solving :}$

$\implies \mathsf {x + 17 + 87 = 180}$

$\implies \mathsf {x + 104 = 180}$

$\implies \mathsf {x = 180 - 104}$

$\implies \mathsf {x = 76}$

8 0

1 year ago