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mezya [45]
3 years ago
5

line j has an equation of y=-x+8. line k includes the point (1,-3) and is perpendicular to line j. what is the equation of line

k?
Mathematics
1 answer:
In-s [12.5K]3 years ago
8 0

Answer:

y = x - 4

Step-by-step explanation:

<u>Use point slope form:  (y - y1) = m(x - x1)</u>

m = 1

<u>Step 1:  Plug in</u>

(y - (-3)) = 1(x - 1)

y + 3 - 3 = x - 1 - 3

y = x - 4

Answer:  y = x - 4

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Mazyrski [523]
The anwser should be c
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3 years ago
Match the right side of the equation to the left side<br> cot x sec^4 x=cot x+ 2 tan x+tan^3 x
Natalka [10]

Step-by-step explanation:

cot x + 2 tan x + tan³ x

Write in terms of sine and cosine:

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(cos⁴ x / (sin x cos³ x) + 2 (sin² x cos² x / (sin x cos³ x)) + (sin⁴ x / (sin x cos³ x))

Add:

(cos⁴ x + 2 sin² x cos² x + sin⁴ x) / (sin x cos³ x)

Factor:

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5 0
3 years ago
Convert 6 4/5 to an improper fraction.
Marina86 [1]
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7 0
2 years ago
What is the slope of the line?
erik [133]
Down 3 over 1
aka -3 is the slope
<span>Your first point is (1,4) The second is (2,1). Use the formula 
y-y
x-x  = slope
4-1
1-2 = slope
3
-1
3/-1 equal to -3</span>
4 0
2 years ago
Read 2 more answers
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Sladkaya [172]

Answer:

You put the numbers twice, so I can't comprehend it.

Step-by-step explanation:

4 0
3 years ago
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