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allochka39001 [22]
3 years ago
13

Can anyone solve this I really need help

Mathematics
1 answer:
earnstyle [38]3 years ago
8 0
The answer is 12.24745 or 5/6
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Solve for x. thank you in advance, please answer my other questions as well im having a tough time
klio [65]

Answer:

3/4

Step-by-step explanation:

log_{(5)} (\sqrt[4]{125})

\frac{log(\sqrt[4]{125}) }{log(5)}

=0.75

8 0
3 years ago
HELP!!!!!!!!!!!!!
Misha Larkins [42]

Answer:

P'(7,0)Q'(2,1) R'(12,-6)

Step-by-step explanation:

P(3,5)------>P'(3+4,5-5)

P'(7,0)

Q(-2,6)----->Q'(-2+4,6-5)

Q'(2,1)

R(8,-1)------>R'(8+4,-1-5)

R'(12,-6)

8 0
4 years ago
2. (08.01) Two lines, R and M, are represented by the following equations: Line R: 2x + 2y = 18 Line M: x + y = 9 Which statemen
bulgar [2K]

Answer:

infinitely many solutions

Step-by-step explanation:

Given the 2 equations

2x + 2y = 18 → (1)

x + y = 9 → (2)

Equation (1) is twice (2)

Thus the equations are equal and will have infinite solutions

7 0
3 years ago
Sue drank 3 glasses of juice. She drank a total of 24.3 ounces. How much did each glass
otez555 [7]

Answer: 8.1 ounces

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A local hamburger shop sold a combined total of 659 hamburgers and cheeseburgers on Sunday. There were 50 fewer cheeseburgers so
NISA [10]

Answer:

The sold 354.5 hamburgers and 300.5 cheeseburgers.

Step-by-step explanation:

Let number of hamburgers=h

Let number of cheeseburgers=c

On Sunday, the shop sold a combined total of 659 hamburgers and cheeseburgers. Therefore:

h+c=659....(I)

There were 50 fewer cheeseburgers sold than hamburgers .

c=h-50.....(ii)

Substitution of equation (ii) into (I)

h+(h-50)=659

2h=659+50

2h=709

h=709/2=354.5

From (ii)

c=h-50

=354.5-50=300.5

The sold 354.5 hamburgers and 300.5 cheeseburgers.

NOTE: These result are from the given data. However, we were not informed if the shop sells half burgers or not

7 0
3 years ago
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