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Amanda [17]
3 years ago
10

What shape is the cross section formed by the intersection of a cone and a plane parallel to the base of the cone?

Mathematics
1 answer:
Ksju [112]3 years ago
7 0
<h2>Answer:</h2>

A circle

<h2>Step-by-step explanation:</h2>

The representation of this problem is shown below. The cross-section is the name for a slice that cuts through a solid. If we move around the height of the cone through its volume, we will find that at every point the cross section will be a circle. The radius of that circle will depend on the point we are on. On the base of the cone, the circle will have the same radius of the cone and the radius will be decreasing when moving until we get to the apex.

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Calculate the area of a circle with a diameter of 0, 8m​
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Answer:

50.24=4squared times pie

Step-by-step explanation:

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3 years ago
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A salesman make both a base salary and also a commission which is a percentage of what he sells . Each month if his sales total
MissTica
Commission / Base Salary
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3 years ago
What is the value of x in the following equation? -3x-2=2x+8
Arlecino [84]

Answer:

-2 =x

Step-by-step explanation:

-3x-2=2x+8

Add 3x to each side

-3x+3x-2=2x+3x+8

-2 = 5x+8

Subtract 8 from each side

-2-8 = 5x+8-8

-10 = 5x

Divide by 5

-10/5 = 5x/5

-2 =x

7 0
3 years ago
A rumor spreads through a small town. Let y ( t ) be the fraction of the population that has heard the rumor at time t and assum
Ivan

Answer:

Differential equation

\frac{dy}{dt} =ky(1-y)

Solution

y=\frac{1}{1+4e^{-0.327t}}

Value of constant k=0.327 days^(-1)

The rumor reaches 80% at 8.48 days.

Step-by-step explanation:

We know

y(t): proportion of people that heard the rumor

y'(t)=ky(1-y), rate of spread of the rumor

Differential equation

\frac{dy}{dt} =ky(1-y)

Solving the differential equation

\frac{dy}{y(1-y)}=k\cdot dt \\\\\int \frac{dx}{y(1-y)} =k \int dt \\\\-ln(1-\frac{1}{y} )+C_0=kt\\\\1-\frac{1}{y} =Ce^{-kt}\\\\\frac{1}{y} =1-Ce^{-kt}\\\\y=\frac{1}{1-Ce^{-kt}}

Initial conditions:

y(0)=0.2\\y(3)=0.4\\\\y(0)=0.2=\frac{1}{1-Ce^0}\\\\1-C=1/0.2\\\\C=1-1/0.2= -4\\\\\\y(3)=0.4=\frac{1}{1+4e^{-3k}} \\\\1+4e^{-3k}=1/0.4\\\\e^{-3k}=(2.5-1)/4=0.375\\\\k=ln(0.375)/(-3)=0.327\\\\\\y=\frac{1}{1+4e^{-0.327t}}

Value of constant k=0.327 days^(-1)

At what time the rumor reaches 80%?

y(t)=0.8=\frac{1}{1+4e^{-0.327t}} \\\\1+4e^{-0.327t}=1/0.8=1.25\\\\e^{-0.327t}=(1.25-1)/4=0.0625\\\\t=ln(0.0625)/(-0.327)=8.48

The rumor reaches 80% at 8.48 days.

8 0
3 years ago
Ivan and Tanya share £150 in the ration of 4:1
Zarrin [17]

Answer:

Money Ivan gets   extra = 120 - 30 (or 3x) = 90

Step-by-step explanation:

Ivan = 4x

Tanya = 1x

Total = 150

4x + x = 150

5x = 150 ;  x = 150 / 5 = 30

Ivan = 4x = 120

Tanya = 1x = 30

Money Ivan gets   extra = 120 - 30 (or 3x) = 90

8 0
3 years ago
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