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3 years ago

The linear momentum is a constant when the mass varies inversely of the velocity. If the velocity is 16 meters per second

Mathematics

1 answer:

Travka [436]3 years ago

8 0

Answer:

The weight for an object with a velocity of 12 meters per second is 600 kilograms

Step-by-step explanation:

Formula of linear momentum : p = mv

where p is the momentum

m = mass

v = velocity

If the velocity is 16 meters per second and the object weighs 450 kilograms

Substitute the values

$p = 16 \times 450$

We are supposed to find the weight for an object with a velocity of 12 meters per second

So, p = 12m

We are given that The linear momentum is a constant when the mass varies inversely of the velocity.

So, $16 \times 450 = 12 m$

$\frac{16 \times 450}{12}=m$

600 = m

So,the weight for an object with a velocity of 12 meters per second is 600 kilograms

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What is the equation of the line in slope-intercept form with slope -3/2 and y-intercept -5?

V125BC [204]

About Slope Intercept Form:

y = mx + b
m represents the slope
b represents the y-intercept or AKA the starting point

ABOUT PROBLEM:

Since -3/2 is the slope, it represents m in Slope Intercept Form
Since -5 is the y-intercept, it represents b in Slope Intrecept Form

y = mx + b

y = -3/2x + -5 --- IN Slope Intercept Form

Hope this helps you!!! :)

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3 years ago

Which ordered pair is generated from the equation shown below? y = 2x + 4 A. (1, 6) B. (1, 2) C. (3, 6) D. (8, 16)

USPshnik [31]

Answer:

The ordered pair generated from the equation is (1, 6).

Step-by-step explanation:

An ordered pair is a pair of numbers, representing two variables, in a specific order. For instance, (<em>x</em>, <em>y</em>) = (1, 2) here <em>x</em> = 1 and <em>y</em> = 2.

The equation provided is:

$y=2x+4$

Check for all the options:

A (1, 6): $y=2x+4\Rightarrow\ 6=(2\times 1) +4\Rightarrow\ 6=6$
B (1, 2): $y=2x+4\Rightarrow\ 2=(2\times 1) +4\Rightarrow\ 2\neq 6$
C (3, 6): $y=2x+4\Rightarrow\ 6=(2\times 3) +4\Rightarrow\ 6\neq10$
D (8, 16): $y=2x+4\Rightarrow\ 16=(2\times 8) +4\Rightarrow\ 16\neq20$

Thus, the ordered pair generated from the equation is (1, 6).

8 0

3 years ago

Which graph shows a system with no solutions? Graph A Graph B Graph C y= 2r-1 2y 4x-2 A. Graph C OB. Graph B C. Graph A

REY [17]

Answer:

graph b

Step-by-step explanation:

7 0

3 years ago

The answer is p = -2/3 and q= -2

igomit [66]

$y=\dfrac{p}{q+x}\\\\\dfrac{1}{y}=\dfrac{1}{\frac{p}{q+x}}=\dfrac{q+x}{p}$

We have x and y intercept:

(2, 0) and (0, 3).

Substitute the coordinates of points to the equation:

$(2,\ 0)\\\\0=\dfrac{q+2}{p}\to q+2=0\to q=-2\\\\(0,\ 3)\\3=\dfrac{q+0}{p}\to3p=q\to3p=-2\to p=-\dfrac{2}{3}$

6 0

3 years ago

(y - 2)2 = y2 – 6y + 4<br> Is this statement true or false?

trasher [3.6K]

<h3>Answer: False</h3>

==============================================

Explanation:

I'm assuming you meant to type out

(y-2)^2 = y^2-6y+4

This equation is not true for all real numbers because the left hand side expands out like so

(y-2)^2

(y-2)(y-2)

x(y-2) .... let x = y-2

xy-2x

y(x)-2(x)

y(y-2)-2(y-2) ... replace x with y-2

y^2-2y-2y+4

y^2-4y+4

So if the claim was (y-2)^2 = y^2-4y+4, then the claim would be true. However, the right hand side we're given doesn't match up with y^2-4y+4

--------------------------

Another approach is to pick some y value such as y = 2 to find that

(y-2)^2 = y^2-6y+4

(2-2)^2 = 2^2 - 6(2) + 4 .... plug in y = 2

0^2 = 2^2 - 6(2) + 4

0 = 4 - 6(2) + 4

0 = 4 - 12 + 4

0 = -4

We get a false statement. This is one counterexample showing the given equation is not true for all values of y.

6 0

3 years ago

Read 2 more answers