Question

Find the measures of angles 1, 2, and 3

Answer 1

Given :-

x = 33°

Then :-

m∠1 = 33° ( angle x and angle 1 are corresponding angles on a transversal )

Which means :-

m∠1 + m∠2 = 90° ( angle 1 and angle 2 are complementary angles )

33 + ∠2 = 90

∠2 = 90 - 33

m∠2 = 57°

Then :-

m∠1 + m∠3 = 180° ( angle 1 and angle 3 are a linear pair )

33 + ∠3 = 180°

∠3 = 180 - 32

m∠3 = 147°

Therefore ,

m∠1 = 33°

m∠2 = 57°

m∠3 = 147°