Answer:
Access installation through shared drive
Explanation:
Answer:
import random
numbers = []
even = 0
odd = 0
for i in range(100):
numbers.append(random.randint(1, 200))
for i in range(100):
if numbers[i] % 2 == 0:
even += 1
else:
odd += 1
print("Even:", even)
print("Odd:", odd)
Explanation:
Gg ez.
Explanation:
Both station will retract their data. They will wait a random amount of time before sending out data again. This lessens the chance of collision again.
Answer:
B.O(n).
Explanation:
Since the time complexity of visiting a node is O(1) in iterative implementation.So the time complexity of visiting every single node in binary tree is O(n).We can use level order traversal of a binary tree using a queue.Which can visit every node in O(n) time.Level order traversal do it in a single loop without doing any extra traversal.
To be honest I feel like it’s B that’s looks and seems the most correct to me
