The answer is C:
In most Franchise businesses, the franchisor provides ongoing guidance and support, and a developed way of doing business. In addition, they offer a higher rate of success as compared to start-up businesses and you may find it easier to secure finances for a franchise. You will get all the benefits that are attached with big businesses for a small business ownership.
Answer: library
Explanation:
A library refers to the collection of software routines that can be used by other software. Licensing terms for this type of software are important for programmers who use the software.
It is the collection of non-volatile resources that is used by computer programs, usually for the development of software.
Jeff pay $2,300 for his computer.
b. $2,300
<u>Explanation:</u>
Consumer surplus can be defined as the amount that the consumer is willing to pay for a product or a service. The word surplus is a synonym for something extra or excess. It corresponds to the extra benefit that the consumer gets while buying something which may be the result of some discount, sale, or negotiation.
Jeff realizes a consumer surplus of $700 while purchasing a laptop of $3000. As the consumer surplus is $700,
the amount Jeff has paid for the laptop is: $3000 - $700
: $2300
Answer: So then every thing is not cluster together and you have everything where you can get to it faster and it just makes everything 100 times better then it not being organized :) hope this helped and if it didn't I'm so sorry
Explanation:
Answer:
In opp friend function is a function that gives the same access to private and protected data. It is declared in class that is granting access.
Explanation:
#include<iostream.h>
using namespace std;
class Sum
{
int a, b, add;
public:
void input()
{
cout << "Enter the value of l and m:";
cin >> l>>m; taking input from users
}
friend void add(sum &t);
void display()
{
cout << "The sum is :" << z;
}
};
void add(sum & p)
{
p.add = p.a + p.b;
}
int main()
{
sum p1;
p1.input();
add(p1);
p1.display();
return false;
if(display==5)
{
return true; //true is returned if sum is equal to 5
}
else //if they are not the same
{
return false;
}
}
