All categories

2 years ago

Sean bought 68 3/4 inches of rope . How many 15-inches ropes can he make from it

2 answers:

6 0

Length of rope bought by Sean = 68 3/4 inches
 = 275/4 inches
Then
The number of 15 inch rope that can be made by Sean = (275/4)/15
 = 275/(4 * 15)
 = 275/60
 = 4.58
So we can see from the above deduction that Sean can make 4 complete 15 inches ropes and there will be 0.58 inches of rope excess. I hope the procedure and the method of solving is absolutely clear to you. This is the easiest way to get to the solution for such problems.

lutik1710 [3]2 years ago

6 0

I first divided 3/4 tk her 0.75
I then got 68.75 as the inches of rope.

If you then divide 68.75/15
you get 4.58333.....

Sean can make 4.58 - 15inch ropes

You might be interested in

Consider the following pair of equations:

miv72 [106K]

$3x + 3 = x - 1 \\ 3x - x = - 1 - 3 \\ 2x = - 4 \\ x = \frac{ - 4}{2 } = - 2$
Take X=-2 into y
$y = x - 1 \\ y = - 2 - 1 \\ y = - 3$
(x, y) =(-2,-3)

6 0

3 years ago

Equation:

jekas [21]

Answer:

x = 41; B = 41°; A = 77°

Step-by-step explanation:

All of the angles add up to 180 so to solve for X you do (x) + (2x-5) + (62) = 180. Solve for X and you get 41. Lastly plut the answer back into the equation.

4 0

3 years ago

Complete the statement, f( ) = -5. Blank 1: Plz answer asap!

tankabanditka [31]

It’s 12 that’s the simple answer

4 0

3 years ago

The sequence$$1,2,1,2,2,1,2,2,2,1,2,2,2,2,1,2,2,2,2,2,1,2,\dots$$consists of $1$'s separated by blocks of $2$'s with $n$ $2$'s i

kicyunya [14]

Consider the lengths of consecutive 1-2 blocks.

block 1 - 1, 2 - length 2

block 2 - 1, 2, 2 - length 3

block 3 - 1, 2, 2, 2 - length 4

block 4 - 1, 2, 2, 2, 2 - length 5

and so on.

Recall the formula for the sum of consecutive positive integers,

$\displaystyle \sum_{i=1}^j i = 1 + 2 + 3 + \cdots + j = \frac{j(j+1)}2 \implies \sum_{i=2}^j = \frac{j(j+1) - 2}2$

Now,

$1234 = \dfrac{j(j+1)-2}2 \implies 2470 = j(j+1) \implies j\approx49.2016$

which means that the 1234th term in the sequence occurs somewhere about 1/5 of the way through the 49th 1-2 block.

In the first 48 blocks, the sequence contains 48 copies of 1 and 1 + 2 + 3 + ... + 47 copies of 2, hence they make up a total of

$\displaystyle \sum_{i=1}^48 1 + \sum_{i=1}^{48} i = 48+\frac{48(48+1)}2 = 1224$

numbers, and their sum is

$\displaystyle \sum_{i=1}^{48} 1 + \sum_{i=1}^{48} 2i = 48 + 48(48+1) = 48\times50 = 2400$

This leaves us with the contribution of the first 10 terms in the 49th block, which consist of one 1 and nine 2s with a sum of $1+9\times2=19$ .

So, the sum of the first 1234 terms in the sequence is 2419.

8 0

1 year ago

Find the slope of the line

Reil [10]

The slope is negative, so the slope is negative. Using the rise over run formula, the slope of the line should be -1.

7 0

3 years ago