How to divide 900,000 divide 1000
1 answer:
Answer: 900
Step-by-step explanation:
To divide 900,000 by 1,000 it might be easier to write it as a fraction:
After doing this, you can cross out the same number of zeros on the numerator and denominator. Since there are three zeros in the denominator, cross out three on the top and bottom. MAKE SURE YOU DON'T CROSS OUT MORE THAN THREE ZEROS IN THE TOP! Always cross out the smallest number of zeros. Also keep in mind that this is only for zeros, not any other number.
Also, there are multiple ways to divide this number but this is one of the easiest ways (other than plugging it in a calculator).
Hope this helps!
You might be interested in
Answer:
a) The 98% confidence interval would be given (0.182;0.218).
b) We are 98% confident that the true proportion of of England people who are deficient in Vitamin D is between 0.182 and 0.218.
c) If repeated samples were taken and the 98% confidence interval computed for each sample, 98% of the intervals would contain the population proportion.
d) Yes since the confidence interval not contains the value 0.25, we can refute the claim at 2% of significance.
Step-by-step explanation:
Data given and notation
n=2700 represent the random sample taken
X represent the people in England who are deficient in Vitamin D
estimated proportion of England people who are deficient in Vitamin D
represent the significance level
Confidence =0.98 or 98%
z would represent the statistic (variable of interest)
p= population proportion of England people who are deficient in Vitamin D
Part a
The confidence interval would be given by this formula
For the 98% confidence interval the value of and
, with that value we can find the quantile required for the interval in the normal standard distribution.
And replacing into the confidence interval formula we got:
And the 98% confidence interval would be given (0.182;0.218).
Part b
We are 98% confident that the true proportion of of England people who are deficient in Vitamin D is between 0.182 and 0.218.
Part c
If repeated samples were taken and the 98% confidence interval computed for each sample, 98% of the intervals would contain the population proportion.
Part d
Yes since the confidence interval not contains the value 0.25, we can refute the claim at 2% of significance.
It is hard to tell your precise intention. Choose the appropriate interpretation.
