Pleas help ASAP.... Thank you
2 answers:
Hey there!
For this problem and future problems like these, you'll want to memorize the phrase "SOHCAHTOA," which indicates which sides of the triangle are equal to which trigonomic function.
Sine = Opposite/Hypotenuse
Cosine = Adjacent/Hypotenuse
Tangent = Opposite/Adjacent
Based on that, you need to know which sides on the triangle are which. I attached an image for reference. The image I attached references the right angle, however, you'll want to reference angle A on your triangle instead, based on the problem.
Based on that, you should be able to easily divide your numbers and get your answer.
Hope this helped you out! :-)
For this problem and future problems like these, you'll want to memorize the phrase "SOHCAHTOA," which indicates which sides of the triangle are equal to which trigonomic function.
Sine = Opposite/Hypotenuse
Cosine = Adjacent/Hypotenuse
Tangent = Opposite/Adjacent
Based on that, you need to know which sides on the triangle are which. I attached an image for reference. The image I attached references the right angle, however, you'll want to reference angle A on your triangle instead, based on the problem.
Based on that, you should be able to easily divide your numbers and get your answer.
Hope this helped you out! :-)
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Answer:
A and C
Step-by-step explanation:
Given
2cos²x - 2 = 0 ( add 2 to both sides )
2cos²x = 2 ( divide both sides by 2 )
cos²x = 1 ( take the square root of both sides )
cos x = ± = ± 1
cos x = 1 ⇒ x = (1) = 0°
cos x = - 1 ⇒ x = (- 1) = 180°