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Ilia_Sergeevich [38]
3 years ago
9

Pleas help ASAP.... Thank you

Mathematics
2 answers:
Bogdan [553]3 years ago
6 0
The answer is (3) 24/26 because Sin is opposite over the hypotenuse so there's how you get 24 over 26
Snezhnost [94]3 years ago
4 0
Hey there!

For this problem and future problems like these, you'll want to memorize the phrase "SOHCAHTOA," which indicates which sides of the triangle are equal to which trigonomic function. 

Sine = Opposite/Hypotenuse 
Cosine = Adjacent/Hypotenuse
Tangent = Opposite/Adjacent

Based on that, you need to know which sides on the triangle are which. I attached an image for reference. The image I attached references the right angle, however, you'll want to reference angle A on your triangle instead, based on the problem. 

Based on that, you should be able to easily divide your numbers and get your answer. 

Hope this helped you out! :-)

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Answer:

See below

Step-by-step explanation:

(a) \:  \: x =  \frac{c}{3}  \\  \\  \implies \:  {x}^{2}  =   { \bigg( \frac{c}{3} \bigg) }^{2}   \\  \\ \bold{\implies \:  {x}^{2}  =     \frac{ {c}^{2} }{9} } \\  \\ (b) \:  \: x + y =  \frac{c}{3}  +  \frac{ac}{4}  \\  \\\implies \:  \bold{x + y  =  \frac{4c + 3ac}{12} } \\  \\  \frac{xy}{z}  =  \frac{ \frac{c}{3}  \times  \frac{ac}{4} }{ \frac{ {a}^{2} }{2c + 1} }  \\  \\ =  \frac{ \frac{ac ^{2} }{12} }{ \frac{ {a}^{2} }{2c + 1} }  \\  \\  =  \frac{a {c}^{2} }{12}  \times  \frac{2c + 1}{ {a}^{2} }  \\  \\  \implies\bold{\frac{xy}{z}  =  \frac{ {c}^{2}(2c + 1) }{12a} }

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2 years ago
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