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2 years ago

15

Add grouping symbols to make the equation true 10-6•2+8=40

1 answer:

Nitella [24]2 years ago

4 0

Your answer should be:
(10-6)x(2+8)=40

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2 years ago

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3 years ago

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Please help me on this I’m super stuck

erastova [34]

Answer:

<u>BC = 3.1666</u>

Step-by-step explanation:

To solve this you need to know that cosine∅ = adjacent/hypotenuse. We already know that hypotenuse = 5 and that ∅ = 70*. By substituting these in you will get cosine 70* = adjacent/5. Evaluate cosine 70* on the calculator and get 0.633... Multiply both sides by 5 and get adjacent is about equal to 3.1666. Because BC is the adjacent side of the triangle, this is the length of BC.

6 0

3 years ago

WILL GIVE BRAINLIEST The sequence 7 21 63 189......shows the number of jumping jacks justin did each week, starting with the fir

vovangra [49]

A

this is a geometric sequence since there exists a common ratio r between the terms

r = $\frac{21}{7}$ = $\frac{63}{21}$ = $\frac{189}{63}$ = 3

B

to obtain the next term in the sequence multiply the previous term by 3

$a_{n+1}$ = 3 $a_{n}$ ← recursive rule

C

the n th term of a geometric sequence is

$a_{n}$ = $a_{1}$ $r^{n-1}$

where $a_{1}$ is the first term in the sequence

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3 0

2 years ago

An arched drainage culvert can be modelled by the function:

Zanzabum

Substitute 136.5 for y.

$136.5=\frac{x(191-x)}{60}$

$8190=x(191-x)$

$8190=191x-x^{2}$

$x^{2} -191x+8190=0$

Compare this equation with $ax^{2} +bx+c=0$

a = 1, b = - 191, c = 8190

$x=\frac{-b+\sqrt{b^{2}-4ac } }{2}$ or

$x=\frac{-b-\sqrt{b^{2}-4ac } }{2}$

$x=\frac{191+\sqrt{191^{2}-4(1)(8190) } }{2}$ or

$x=\frac{191-\sqrt{191^{2}-4(1)(8190) } }{2}$

$x=\frac{191+\sqrt{36481-32760 } }{2}$ or

$x=\frac{191-\sqrt{36481-32760 } }{2}$

$x=\frac{191+\sqrt{3721 } }{2}$ or

$x=\frac{191-\sqrt{3721 } }{2}$

$x=\frac{191+61}{2}$ or

$x=\frac{191-61}{2}$

$x=\frac{252}{2}$ or

$x=\frac{130}{2}$

x = 126 or x = 65

Hence, the points on the curve are (65, 136.5) and (126, 136.5).

The width of the air space is the distance between these points.

Width = $\sqrt{(x_{2}- x_{1})^{2} +( y_{2}- y_{1}) ^{2}$

= $\sqrt{(126- 65)^{2} +(136.5-136.5) ^{2}$

= 126 - 65

= 61

Hence, width of the air space is 61m.

5 0

2 years ago