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Anna11 [10]
3 years ago
11

The dot plots show rainfall totals for several spring

Mathematics
2 answers:
Alekssandra [29.7K]3 years ago
5 0

Answer:

highlands A. 16

lowlands B. 12

Step-by-step explanation:

tiny-mole [99]3 years ago
3 0

Highland Storms: 15.27mm Lowland: 12.05mm

It would be A for both.

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klasskru [66]
1,132 people came to watch the balloon festival.
3 0
3 years ago
I dont understand this question <br> . Help me please
fiasKO [112]

Answer:

12 ft

Step-by-step explanation:

P=2L+2w

56=2(w+4)+2w

56=2w+8+2w

56=4w+8

4w=48

w=12

7 0
3 years ago
A
UkoKoshka [18]

The dilation of the rectangle stretches it with regards to the distances from the central point

The option that gives the coordinates of the point <em>D</em> is the option;

D (0, 5)

Reason:

The known parameter;

Coordinates of the center of dilation is M(-3, -4)

Scale factor of dilation = 3

The coordinates of the vertex of the rectangle ABCD are;

A(-2, 2), B(3, 2), C(3, -1), and D(-2, -1)

Length MD = \sqrt{(-3 - (-2))^2 + (-4 - (-1))^2} = \sqrt{10}

Therefore, length of MD' = 3·√10

Slope of MD, is given as follows;

  • Slope, \ m = \dfrac{-1 - (-4)}{-2 - (-3)}  = \dfrac{3}{1}  = 3

Therefore, y = 3·x

x² + y² = (3·√10)²

x² + (3·x)² = (3·√10)²

10·x² = 90

x = 3

y = 9

We note that the value of <em>x</em>, and <em>y</em>, are calculated as distance from the central point, <em>M</em>, therefore;

The coordinates of the point D' is (-3 + x, -4 + y)

∴ Coordinates of D' = (-3 + 3, -4 + 9) = (0, 5)

  • Coordinates of D' = (0, 5)

Learn more about dilation of a figure from a point here:

brainly.com/question/13625798

4 0
3 years ago
A piece of wire 25 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria
fomenos

Answer:

Wire used for square is 7.55 m.

Step-by-step explanation:

Let the length of wire cut for square be 'x'.

Given:

Total length of the wire = 25 m

Length of wire for square = 'x'

Length of wire for equilateral triangle = 25-x

Now, area of square (a) = x^2

Area of equilateral triangle (e) is given as:

e=\frac{\sqrt3}{4}(25-x)^2

Now, total area (A) is given as:

A=a+e\\\\A=x^2+\frac{\sqrt3}{4}(25-x)^2

Now, in order to maximize 'A', the derivative of area with respect to 'x' must be 0.

∴ \frac{dA}{dx}=0

\frac{d}{dx}(x^2+\frac{\sqrt3}{4}(25-x)^2)=0\\\\2x-\frac{\sqrt3}{2}(25-x)=0\\\\2x+\frac{x\sqrt3}{2}=\frac{25\sqrt3}{2}\\\\x(2+\frac{\sqrt3}{2})=\frac{25\sqrt3}{2}\\\\x(4+\sqrt3)=25\sqrt3\\\\x=\frac{25\sqrt3}{4+\sqrt3}=7.55\ m

Therefore, the length of the wire that is cut for square should be 7.55 m for maximum area.

3 0
3 years ago
Which point is located on the line represented by the equation y+4=-5(x-3)?
Elis [28]

The answer would be (3,-4) This is because if you replace the variables with the numbers and solve the equation it will come out 0=0

So, lets solve.

y+4=-5(x-3)

-4+4=-5(3-3)

0=-5x0

0=0

So therefore the correct answer will be (3,-4)

Hope this helped

8 0
3 years ago
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