All categories

3 years ago

Hey can you please help me posted picture of question help

Mathematics

2 answers:

Anuta_ua [19.1K]3 years ago

8 0

(4x^7-x+6)-(x^7+3)=
4x^7-x+6-x^7-3=
(4-1)x^7-x+3=
3x^7-x+3

Answer: Option C. 3x^7-x+3

Maru [420]3 years ago

3 0

Hey there :)

( 4x⁷ - x + 6 ) - ( x⁷ + 3 )

Distribute the " - " sign into the brackets
4x⁷ - x + 6 - x⁷ - 3

Combine like-terms
4x⁷ - x⁷ - x + 6 - 3
3x⁷ - x + 3

Your answer will be $\boxed {Option \ C }$

You might be interested in

Steven and James are both about to take a math test. Steven is experiencing shortness of breath and profuse sweating in anticipa

Firlakuza [10]

Answer:

james

Step-by-step explanation:

5 0

3 years ago

Solve two sevenths plus seven fourteenths (2 points)

Law Incorporation [45]

Answer:

2/7 + 7/14 = 11/14

Step-by-step explanation:

7 x -2 = -14 Each seventh is going to be worth 2 fourteenths!

This means 2/7 = 4/14

4/14 + 7/14 = 11/14

6 0

2 years ago

I have trouble with the converting

Gnom [1K]

HI,
3 yd= 108 in
24 ft = 8 yd
56 ft= 18 yd 6 ft
12 ft 6 in = 216 in ( im not 100% sure on this one)
i hope this helped you

7 0

3 years ago

IM DOING A TEST! Idk how to do this help Please try

goldenfox [79]

Answer:

1 is 102

2 is 78

~~~~~~~~~~~~~~~~~~~~

Always double check :)

7 0

3 years ago

Read 2 more answers

1. What are foci? 2. What is the first step to take to write the equation of a hyperbola? 3. How do you represent parts of a hyp

Andrei [34K]

Answer: see below

Step-by-step explanation:

1) Foci is plural for Focus. Since a hyperbola has two focus points, they are referred to as foci. The foci is where the sum of the distances from any point on the curve to the foci is constant.

2) When determining the equation of a hyperbola you need the following:

a) does the hyperbola open up or to the right?

b) what is the center (h, k) of the hyperbola?

c) What is the slope of the asymptotes of the hyperbola?

3) The equation of a hyperbola is:

$\dfrac{(x-h)^2}{a^2}-\dfrac{(y-k)^2}{b^2}=1\qquad or\qquad \dfrac{(y-k)^2}{b^2}-\dfrac{(x-h)^2}{a^2}=1$

(h, k) is the center of the hyperbola
± b/a is the slope of the line of the asymptotes
The equation starts with the "x" if it opens to the right and "y" if it opens up

5 0

3 years ago