Solution:
The process of transaction can guarantee the reliability of business applications. Locking resources is widely used in distributed transaction management (e.g; two phase commit, 2PC) to keep the system consistent. The locking mechanism, however, potentially results in various deadlocks. In service oriented architecture, the deadlock problem becomes even worse because multiple transactions try to lock shared resources in the unexpectable way due to the more randomicity of transaction requests, which has not been solved by existing research results. In this paper, we investigate how to prevent local deadlocks, caused by the resource competition among multiple sub-transactions of a gl obal transaction, and global deadlocks from the competition among different global transactions. We propose a replication based approach to avoid the local deadlocks, and a timestamp based approach to significantly mitigate the global deadlocks. A general algorithm is designed for both local and global deadlock prevention. The experimental results demonstrate the effectiveness and efficiency of our deadlock prevention approach. Further, it is also proved that our approach provides higher system performance than traditional resource allocation schemes.
This is the required answer.
Answer:
A. Multifactor authentication
Explanation:
Multifactor authentication is a security system process that requires a user to verify his or her identity by providing two categories of credentials.
A mobile device user has entered her user ID and password to access an online account, she immediately receives a text message with a unique PIN or One Time Password (OTP) that must be entered before she is granted access to the account. This is an example of a multifactor authentication security method.
It really is hard to say because there are many slots and we do not know what your teacher is teaching. I have seen a lot of teachers teaching out of date material. With that said, here is a list from best to worst.
PCI Express x16
PCI Express x1
AGP
PCI
This is list is based on greatest to least and base on the bandwidth read and write speed.
Answer:
Command: Systemoutprintln (b)
Output: 7
Explanation:
To solve this problem, we must take into account the precedence of operation.
The division takes precedence before the addition, so we must divide before we add for b.
So
int b = 4 + 6/2 = 4 + 3 = 7.
So
Command: Systemoutprintln (b)
Output: 7
