All categories

3 years ago

This is solving quadratic equations

Mathematics

2 answers:

Drupady [299]3 years ago

8 0

Answer: " x = $\frac{2}{5}$ ; 0 " .

__________________________________

Or; write in "decimal form" ; as:

" x = 0.4 ; 0 " .

__________________________________

Step-by-step explanation:

__________________________________

Given:

10x² - 4x = 0 ; Solve for "x" .

__________________________________

Factor out a "2x" from the "left-hand side" of the equation:

2x (5x - 2) = 0 ;

Note that "any value"; multiplied by "0" ; equals "0" ;

We have 2 (two) expressions:

1) " 2x " ; And:

2) " (5x - 2) " ;

→ which, when multiplied together, equal "0" ;

So, set "each" of the 2 (two) expressions "equal to 0 " ;

and solve for "x" ;

____________________________________

1) " 2x = 0 " ; solve for "x" ;

Divide each side of the equation by: "2" ;

to isolate "x" on one side of the equation;

& to solve for "x" ;

→ 2x/2 = 0/2 ;

→ x = 0 ;

__________________________________

2) " 5x - 2 = 0 " ; solve for "x" ;

Add "2" to each side of the equation :

5x - 2 + 2 = 0 + 2 ;

to get: 5x = 2 ;

Now ; divide each side of the equation by: "5" ;

to isolate "x" on one side of the equation;

& to solve for "x" ;

5x/5 = 2/5 ;

to get:

x = 2/5 ;

__________________________________

The answer is: " x = $\frac{2}{5}$ ; 0 . "

__________________________________

Or; write in "decimal form" ; as:

" x = 0.4 ; 0 " .

__________________________________

Hope this is helpful to you!

Best wishes!

__________________________________

Alexandra [31]3 years ago

6 0

➖➖➖➖➖➖
10x^2 - 4x = 0
2x ( 5x - 2 ) = 0
x = [ 0 + 2 / 5 ]

x = 0 , 2/5 // ✔️
➖➖➖➖➖➖

You might be interested in

What is the value of p?<br><br> p+1/5−1/2=1/10

kotegsom [21]

P+1/5−1/2=1/10
p+ 10÷5= 2×1=2 =1/10
10÷2= 5*(-1)= -5=1/10

2-5/10

p-3/10 = 1/10
p= 1/10+3/10
p= 4/10

4÷2= 2
10÷2 = 5
>The answer is:
>> P= 2/5

3 0

3 years ago

In ΔXYZ, ∠X=82° and ∠Y=84°. ∠XWZ=90° and XY=97. Find the length of XW to the nearest integer.

ivanzaharov [21]

Check the picture below to the left, let's use those sides with the law of sines

$\textit{Law of sines} \\\\ \cfrac{sin(\measuredangle A)}{a}=\cfrac{sin(\measuredangle B)}{b}=\cfrac{sin(\measuredangle C)}{c} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{sin(14^o)}{97}=\cfrac{sin(84^o)}{XZ}\implies XZ = \cfrac{97\cdot sin(84^o)}{sin(14^o)}\implies XZ \approx 398.76 \\\\\\ \stackrel{\textit{now using SOH CAH TOA}}{cos(82^o) = \cfrac{XW}{XZ}}\implies XZcos(82^o)=XW \\\\\\ 398.76cos(82^o)\approx XW\implies 55.497\approx XW\implies \stackrel{\textit{rounded up}}{55=XW}$

7 0

2 years ago

Why does it take 3 copies of 1/6 to show the same amount as 1 copy of 1/2?

antiseptic1488 [7]

You can solve this by putting the number of copies in the top part of the fraction. If you replace the one in the top part of 1/6 with 3, you get the fraction 3/6. Half of six is three and half of two is one, so both fractions are equal. You can test this be dividing the 3 in the top by 3 and the 6 in the bottom by three. Your result will be 1/2. Although there are three times ad many copies, each copy is three times as small, so it balances out.

6 0

3 years ago

21. For the following exercises, use the descriptions of each pair of lines given below to find the slopes of Line 1 and Line 2.

dybincka [34]

Answer:

The given lines are perpendicular.

Step-by-step explanation:

In the question, two lines are given as line 1 passes through (1,7) and (5,5). Whereas, line 2 passes through (-1,-3) and (1,1).

It is required to find the slope of given lines and figure out whether they are perpendicular, parallel or neither.

To solve this question, first find the slope of both lines. Check if their product is equal to -1, then they are perpendicular. If the slopes are equal the lines are parallel.

Step 1 of 2

Find the slope of first line.

$\begin{aligned}m_{1} &=\frac{5-7}{5-1} \\m_{1} &=\frac{-2}{4} \\m_{1} &=-\frac{1}{2}\end{aligned}$