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4 years ago

What is 2/3 of 6 days?

Mathematics

2 answers:

kolezko [41]4 years ago

7 0

4 days.

When multiplying across:

2/3 • 6/1 = 2/1 • 2/1 = 4

6 and 3 reduce.

Ganezh [65]4 years ago

5 0

You do 6 divided by 3 which is 2
Then you do 2 times 2 which is 4 and 4 is your answer

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Which function has real zeros at x = 3 and x = 7?

atroni [7]

Answer:

x = 3 x = 7 Okay well I got C. f(x) = x2 - 10x + 21 I got it because u subtract and add at the last part.

Step-by-step explanation:

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3 years ago

What is the area of the trapezoid shown below?

Olegator [25]

Answer:

Step-by-step explanation:

7+8/2 multiply by 6

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4 years ago

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Choose the answer.

kiruha [24]

B) about 400 -not sure

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3 years ago

Read 2 more answers

(1 point) a tank contains 1060 l of pure water. a solution that contains 0.06 kg of sugar per liter enters the tank at the rate

kirill115 [55]

(a) There is 0 kg of sugar in the tank at the beginning since it contains pure water at the start. The sugar only comes from the solution.

(b)

$S' = f(t,S) = \left(0.06 \dfrac{\text{kg}}{\text{L}}\right)\left(9\dfrac{\text{L}}{\text{min}}\right) - \left(\dfrac{S}{1060} \dfrac{\text{kg}}{\text{L}}\right)\left(9\dfrac{\text{L}}{\text{min}}\right) \ \Rightarrow \\ \\ S' = 0.54 \text{ kg}/\text{min} - \dfrac{9S}{1060}$

So yes, you enter S' = 0.54 - (9S/1060)

(c)

$\displaystyle\frac{dS}{dt} = 0.54 - \frac{9S}{1060} \ \Rightarrow\ \frac{dS}{dt} = \frac{572.4 - 9S}{1060}\ \Rightarrow\ \dfrac{dS}{572.4 - 9S} = \frac{1}{1060} dt\ \Rightarrow \\ \\
\int \dfrac{dS}{572.4 - 9S} = \int \frac{1}{1060} dt\ \Rightarrow\textstyle\ -\frac{1}{9}\ln|572.4 - 9S| = \frac{1}{1060}t + C \\ \\
S(0) = 0 \ \Rightarrow\ -\frac{1}{9}\ln|572.4 - 0| = \frac{1}{1060}(0) + C\ \Rightarrow\ C = -\frac{1}{9} \ln 572.4$

$-\frac{1}{9}\ln|572.4 - 9S| = \frac{1}{1060}t -\frac{1}{9} \ln 572.4\ \Rightarrow \\ \\
\ln|572.4 - 9S| = \ln 572.4 - \frac{9}{1060}t \ \Rightarrow \\ \\
|572.4 - 9S| = e^{\ln 572.4 - 9t/1060}\ \Rightarrow \\ \\
572.4 - 9S= \pm 572.4 e^{-9t/1060}\ \Rightarrow \\ \\
S = \frac{-1}{9}\left(-572.4 \pm 572.4 e^{-9t/1060}\right)$

But only (+) satisfies $S(0) = 0$

$S= -\frac{1}{9}\left(-572.4 + 572.4 e^{-9t/1060}\right) \\ \\
S= 63.6 - 63.6 e^{-9t/1060}\text{ kg}$

Enter in S = 63.6 - 63.6 * e^(-9t/1060)

3 0

3 years ago

Find the equation of the tangent line to the graph of f(x) = x2 – 8 at the point (4,8).

makvit [3.9K]

Answer:

f'(4) = 8 tangent of f(x) at (4,8)

Step-by-step explanation:

f(x) = x^2 - 8

f'(x) = 2x

f'(4) = 2*4 = 8 tangent of f(x) at (4,8)

5 0

3 years ago