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Andrew [12]
3 years ago
10

Help with this question please

Mathematics
2 answers:
romanna [79]3 years ago
5 0

Answer:

9 gallons

Step-by-step explanation:

1 gallon = 20 miles

We need to find how many gallons it takes for the car to go 180 miles

So, we need to divide 180 by 20 to find the # of gallons

180/20 = 9

alukav5142 [94]3 years ago
4 0
At 180 miles it will travel at 60
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A luxury chairs manager found that an employee made 3/4 of a chair every 3/8 of an hour
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Answer:

Step-by-step explanation:

(3c/4)/(3h/8)

(3c/4)(8/3h)

(24/12)c/h

2 c/h

So employee can make 2 chairs in one hour.

7 0
2 years ago
On a morning of a day when the sun will pass directly​ overhead, the shadow of a 60​-ft building on level ground is 25 ft long.
AysviL [449]

Answer:

The shadow is decreasing at the rate of 3.55 inch/min

Step-by-step explanation:

The height of the building = 60ft

The shadow of the building on the level ground is 25ft long

Ѳ is increasing at the rate of 0.24°/min

Using SOHCAHTOA,

Tan Ѳ = opposite/ adjacent

= height of the building / length of the shadow

Tan Ѳ = h/x

X= h/tan Ѳ

Recall that tan Ѳ = sin Ѳ/cos Ѳ

X= h/x (sin Ѳ/cos Ѳ)

Differentiate with respect to t

dx/dt = (-h/sin²Ѳ)dѲ/dt

When x= 25ft

tanѲ = h/x

= 60/25

Ѳ= tan^-1(60/25)

= 67.38°

dѲ/dt= 0.24°/min

Convert the height in ft to inches

1 ft = 12 inches

Therefore, 60ft = 60*12

= 720 inches

Convert degree/min to radian/min

1°= 0.0175radian

Therefore, 0.24° = 0.24 * 0.0175

= 0.0042 radian/min

Recall that

dx/dt = (-h/sin²Ѳ)dѲ/dt

= (-720/sin²(67.38))*0.0042

= (-720/0.8521)*0.0042

-3.55 inch/min

Therefore, the rate at which the length of the shadow of the building decreases is 3.55 inches/min

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Answer:

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Bezzdna [24]
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8 0
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