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musickatia [10]
3 years ago
5

What is 6,666,666×100

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
4 0
6,666,666 times 100 equals to 666,666,600
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What is the domain of square root x+6 substract 7
creativ13 [48]
Y=√(x+6) - 7

constraint: x+6> or = 0
or x> 0r = -6
RANGE = x∈R/ x > or = 0
3 0
3 years ago
Which graphs below represent an exponential function? Select all that apply.
Troyanec [42]
The two graphs in the second picture are the graphs of exponential functions. You can detect it from the L shaped graphs. 

The very first graph represents a linear function. A straight line always represents a linear function. In a Linear function, the change in the values of y is constant throughout in relative to change in x values.

The final graph represents a quadratic function rising on both ends. 

Therefore, option b and c are the correct answers
8 0
3 years ago
Read 2 more answers
ILL GIVE BRAINLIEST... HURRY PLZ
Alexeev081 [22]

12 Pairs

4 pairs = 8

2 pairs = 4

8 + 4 = 12

If you need total socks, there's 24 total

7 0
3 years ago
The system of equations may have a unique solution, an infinite number of solutions, or no solution. Use matrices to find the ge
Leno4ka [110]

Answer:

Infinite number of solutions.

Step-by-step explanation:

We are given system of equations

5x+4y+5z=-1

x+y+2z=1

2x+y-z=-3

Firs we find determinant of system of equations

Let a matrix A=\left[\begin{array}{ccc}5&4&5\\1&1&2\\2&1&-1\end{array}\right] and B=\left[\begin{array}{ccc}-1\\1\\-3\end{array}\right]

\mid A\mid=\begin{vmatrix}5&4&5\\1&1&2\\2&1&-1\end{vmatrix}

\mid A\mid=5(-1-2)-4(-1-4)+5(1-2)=-15+20-5=0

Determinant of given system of equation is zero therefore, the general solution of system of equation is many solution or no solution.

We are finding rank of matrix

Apply R_1\rightarrow R_1-4R_2 and R_3\rightarrow R_3-2R_2

\left[\begin{array}{ccc}1&0&1\\1&1&2\\0&-1&-3\end{array}\right]:\left[\begin{array}{ccc}-5\\1\\-5\end{array}\right]

ApplyR_2\rightarrow R_2-R_1

\left[\begin{array}{ccc}1&0&1\\0&1&1\\0&-1&-3\end{array}\right]:\left[\begin{array}{ccc}-5\\6\\-5\end{array}\right]

Apply R_3\rightarrow R_3+R_2

\left[\begin{array}{ccc}1&0&1\\0&1&1\\0&0&-2\end{array}\right]:\left[\begin{array}{ccc}-5\\6\\1\end{array}\right]

Apply R_3\rightarrow- \frac{1}{2} and R_2\rightarrow R_2-R_3

\left[\begin{array}{ccc}1&0&1\\0&1&0\\0&0&1\end{array}\right]:\left[\begin{array}{ccc}-5\\\frac{13}{2}\\-\frac{1}{2}\end{array}\right]

Apply R_1\rightarrow R_1-R_3

\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]:\left[\begin{array}{ccc}-\frac{9}{2}\\\frac{13}{2}\\-\frac{1}{2}\end{array}\right]

Rank of matrix A and B are equal.Therefore, matrix A has infinite number of solutions.

Therefore, rank of matrix is equal to rank of B.

4 0
3 years ago
Plz help asap not very good @ math
Nikitich [7]

The function is going downward

Answer is D.

As x approaches negative infinity, the function approaches negative infinity.

3 0
3 years ago
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