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dexar [7]
3 years ago
6

Which transformation(s) can map ΔLMN onto ΔL'M'N'?

Mathematics
2 answers:
Volgvan3 years ago
7 0
The answer is rotation then translation. (:
Dafna1 [17]3 years ago
3 0

Answer:

Rotation and translation.

Step-by-step explanation:

A clockwise rotation followed by a translation.

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Can you help me please<br> -5 3/4 - 3 1/2=
viktelen [127]

Answer:

-9 1/4

Step-by-step explanation:

6 0
2 years ago
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Tom races his bicycle for 140 ft. A wheel of his bicycle turns 35 times as the bicycle travels this distance. What is the diamet
inna [77]

Answer:

1.3 ft

Step-by-step explanation:

perimeter = 140/35 = 4 ft

diameter = 4 ft/ 3.14 = 1.3 ft

6 0
3 years ago
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The quotient of a number c and 2 is-16​
My name is Ann [436]

Answer:

c=-32

Step-by-step explanation:

c/2=-16

c=-16*2

c=-32

3 0
3 years ago
A ball is thrown up in the air, and it's height (in feet) as a function of time (in seconds) can be written as h(t) = -16t2 + 32
olga2289 [7]

Answer:

1) Using properties of the quadratic equation:

Here the height equation is:

h(t) = -16t^2 + 32t + 6

We can see that the leading coefficient is negative, this means that the arms of the graph will open downwards.

Then, the vertex of the quadratic equation will be the maximum.

Remember that for a general quadratic equation:

a*x^2 + b*x + c = y

the x-value of the vertex is:

x = -b/2a

Then in our case, the vertex is at:

t = -32/(2*-16) = 1

The maximum height will be the height equation evaluated in this time:

h(1) = -16*1^2 + 32*1 + 6 = 22

The maximum height is 22ft

2) Second method, using physics.

We know that an object reaches its maximum height when the velocity is equal to zero (the velocity equal to zero means that, at this point, the object stops going upwards).

If the height equation is:

h(t) = -16*t^2 + 32*t + 6

the velocity equation is the first derivation of h(t)

Remember that for a function f(x) = a*x^n

we have that:

df(x)/dx = n*a*x^(n-1)

Then:

v(t) = dh(t)/dt = 2*(-16)*t + 32 + 0

v(t) = -32*t + 32

Now we need to find the value of t such that the velocity is equal to zero:

v(t) = 0 = -32*t + 32

       32*t = 32

            t = 32/32 = 1

So the maximum height is at t = 1

(same as before)

Now we just need to evaluate the height equation in t = 1:

h(1) = -16*1^2 + 32*1 + 6 = 22

The maximum height is 22ft

4 0
3 years ago
What is the slope of the line x + 6y= 12
Lubov Fominskaja [6]

x + 6y = 12

You want the y-value to be on one side of the equation, so you have to subtract the x-value from both sides.

6y = -x + 12

Next, you divide both sides by 6, so that the y-value will be by itself.

y = - \frac{1}{6} + 2

We know that the slope or the 'm' value is located before the x-value based on y = mx +b, therefore the slope is - \frac{1}{6}

5 0
3 years ago
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