I'm reading this as

with

.
The value of the integral will be independent of the path if we can find a function

that satisfies the gradient equation above.
You have

Integrate

with respect to

. You get


Differentiate with respect to

. You get
![\dfrac{\partial f}{\partial y}=\dfrac{\partial}{\partial y}[x^2e^{-y}+g(y)]](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cpartial%20f%7D%7B%5Cpartial%20y%7D%3D%5Cdfrac%7B%5Cpartial%7D%7B%5Cpartial%20y%7D%5Bx%5E2e%5E%7B-y%7D%2Bg%28y%29%5D)


Integrate both sides with respect to

to arrive at



So you have

The gradient is continuous for all

, so the fundamental theorem of calculus applies, and so the value of the integral, regardless of the path taken, is
Answer:
1/2ft
Step-by-step explanation:
15/28=(5/7)(1 1/2)(w)
15/28=(5/7)(3/2)w
15/28=(15/14)w
(15/28)/(15/14)=w
(15/28)*(14/15)=w
w=14/28
w=1/2 ft
Add. I’m not sure because there is a - besides the 15.
Explanation - 12 + 15 = 27.
Hopefully this helps. Have a blessed one. God loves you. ☺️
Answer:
nope
Step-by-step explanation:
but it's probably better than where i am
Answer:
D. is correct!
Step-by-step explanation:
ht tps://us-static.z-dn.net/fil es/ded/302e17a93f9f7dceb0b9635c302342ae.jp g
^ just an example
brainliest?