I believe The answer is B 40
Answer is (A). (X’ , Y’) = (x, y-6)
If the point U is between points T and V, then the numerical length of TV is 29 units
<h3>How to determine the numerical length of segment TV?</h3>
From the question, we have the following lengths that can be used in our computation:
- Length TU = 18 units
- Length UV = 11 units
The above parameters and representations implies that the point U is between endpoints T and V
This also means that the length TV is longer than the other lengths TU and TV
So, we have the following length equation
TV = TU + UV
Substitute the known values in the above equation
So, we have the following equation
TV = 18 + 11
Evaluate the sum of the like terms in the above equation
So, we have the following equation
TV = 29
Hence, the numerical length of segment TV is 29 units
Read more about lengths at
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<u>Possible question</u>
If tu = 18 and uv = 11 what is tv, if point u is between points t and v
Regroup terms
2(x + 2) = 1
Divided both sides by 2
x + 2 = 1/2
Subtract 2 from both sides
x = 1/2 - 2
Simplify 1/2 - 2 to -3/2
<u>x = -3/2</u>
