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cestrela7 [59]
3 years ago
10

in a certain town, 10% of people commute to work by bicycle. if a person is selected randomly from the town, what are the odds a

gainst selecting someone who commutes by bicycle?
Mathematics
1 answer:
Soloha48 [4]3 years ago
7 0
The odds against selecting someone who commutes by bicycle is 90%
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Please help !!! :(<br> 1 and 2 form a linear pair, if the measure of 1 is 113 find the measure of 2
anzhelika [568]

Answer:

67

Step-by-step explanation:

A linear pair is two angles which form a straight angle when combined (or 180 degrees). Thus do 180 - 113 to get 67 degrees for Angle 2

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Please help!! Needed ASAP!!
yarga [219]

Answer and Explanation:

If, on the other hand, the graph "flexes" or "flattens out" to some degree when it goes to cross the axis, then the zero is of a higher multiplicity; that is, it'll be of multiplicity three, five, or higher.

When a graph doesn't start at 0, it means that the graphs before it is not shown.

For number 4, I'd suggest Graph 3.

For number 3, I'd suggest graph 1.

For number 5, Write something along the lines of "Graph 2 does not show the car stopping slowly, it stops suddenly. Then it starts going really fast and stops suddenly again."

I hoped this helped.

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3 years ago
|x| + 6 = 3 <br><br> A question on homework
alexdok [17]

Answer:

-9

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5 0
3 years ago
Algebra:<br> simplify<br> 4y-6(5z-2y)-2z
gladu [14]

Answer:

16y−32z

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6 0
3 years ago
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Two groups of students were asked how many hours they spent reading each day. The table below shows the numbers for each group:
marta [7]

Solution:

Data represented as number of hours spent in studying by Group A Students:

 1,2,1,1,3,3,2,2,3

Arranging it in ascending order: 1,1,1 ,2, 2, 2, 3, 3, 3,

As number of terms is odd, The median will be middle value of observation.Which is 2.

The Data arranged in ascending order are , (1,1,1,2),2(2,3,3,3).

Median of (1,1,1,2) = Q_{1}=1

Median of (2,3,3,3)=Q_{3}=3

D_{1}=Interquartile Range =Q_{3}-Q_{1}=3-1=2

For Data Set 2,

The Data for group B students are:  3   2 3 2 2 2 1 1 2

Arranging in ascending order: 1,1,2,2,2,2,2,3,3

total number of observation = 9

Median = 2

Arranging the data as : (1,1,2,2) 2,(2,2,3,3)

Median of (1,1,2,2)= Number of observation is 4 which is even , so Median=Q_{1} =  \frac{1+2}{2}=\frac{3}{2}

Median of (2,2,3,3)=Q_{3}= \frac{3+2}{2}=\frac{5}{2}

S=Interquartile Range = Q_{3}-Q_{1}=\frac{5}{2}-\frac{3}{2}=1

D_{1}= S + 1

Interquartile range for Group A Students =Interquartile range for Group B students + 1

Option (D) The interquartile range for Group A employees is 1 more than the interquartile range for Group B students is true.

8 0
3 years ago
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