Solution:
Data represented as number of hours spent in studying by Group A Students:
  1,2,1,1,3,3,2,2,3
Arranging it in ascending order: 1,1,1 ,2, 2, 2, 3, 3, 3, 
As number of terms is odd, The median will be middle value of observation.Which is 2.
The Data arranged in ascending order are , (1,1,1,2),2(2,3,3,3).
Median of (1,1,1,2) =  =1
=1 
Median of (2,3,3,3)= =3
=3
 =Interquartile Range =
=Interquartile Range = =3-1=2
=3-1=2
For Data Set 2,
The Data for group B students are:  3   2	3	2	2	2	1	1	2 
Arranging in ascending order: 1,1,2,2,2,2,2,3,3
total number of observation = 9
Median = 2
Arranging the data as : (1,1,2,2) 2,(2,2,3,3)
Median of (1,1,2,2)= Number of observation is 4 which is even , so Median= =
 =  
Median of (2,2,3,3)= =
= 
S=Interquartile Range =  =
=

Interquartile range for Group A Students =Interquartile range for Group B students + 1
Option (D) The interquartile range for Group A employees is 1 more than the interquartile range for Group B students is true.