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Arturiano [62]
4 years ago
12

How can x^2=x^2+2x+9 be set up as a system of equations

Mathematics
1 answer:
Nikitich [7]4 years ago
8 0

Answer: \left \{ {{y=x^{2} } \atop {y=x^2+2x+9}} \right.

Step-by-step explanation:

1. As you can see, x^{2} is equal to the other quadratic equation x^2+2x+9.

2. Then, this would the same as write the quadratic equations as following:

y=x^{2}

y=x^2+2x+9

3. And then set them equal to each other, as you can see below:

y=y

Substituting, you obtain:

x^{2}=x^2+2x+9

3. Keeping the above on mind, you can set up the given equations as a system of equations as folllowing:

\left \{ {{y=x^{2} } \atop {y=x^2+2x+9}} \right.

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can yall help me pls? thanks just pls tell me the right coordinates on this graph pls if u will :) <3
skelet666 [1.2K]

Answer:

a- (3,4)

b- (0,-4)

c- (-6,2)

d- (0,5)

e- (-4,-5)

Step-by-step explanation:

hope this helps

4 0
3 years ago
What is the value of x in the equation 3(2x + 8) = 0? Group of answer choices −8 −4 4 8 please hurry!
Dafna11 [192]

Answer:

-4

Step-by-step explanation:

3(2x+8) = 0

Distribute

6x + 24 = 0

24 = -6x + 0

24/-6  = -4

8 0
3 years ago
Calculus Problem
Roman55 [17]

The two parabolas intersect for

8-x^2 = x^2 \implies 2x^2 = 8 \implies x^2 = 4 \implies x=\pm2

and so the base of each solid is the set

B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, |x^2-(8-x^2)| = 2|x^2-4|. But since -2 ≤ x ≤ 2, this reduces to 2(x^2-4).

a. Square cross sections will contribute a volume of

\left(2(x^2-4)\right)^2 \, \Delta x = 4(x^2-4)^2 \, \Delta x

where ∆x is the thickness of the section. Then the volume would be

\displaystyle \int_{-2}^2 4(x^2-4)^2 \, dx = 8 \int_0^2 (x^2-4)^2 \, dx \\\\ = 8 \int_0^2 (x^4-8x^2+16) \, dx \\\\ = 8 \left(\frac{2^5}5 - \frac{8\times2^3}3 + 16\times2\right) = \boxed{\frac{2048}{15}}

where we take advantage of symmetry in the first line.

b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

\dfrac\pi8 \left(2(x^2-4)\right)^2 \, \Delta x = \dfrac\pi2 (x^2-4)^2 \, \Delta x

We end up with the same integral as before except for the leading constant:

\displaystyle \int_{-2}^2 \frac\pi2 (x^2-4)^2 \, dx = \pi \int_0^2 (x^2-4)^2 \, dx

Using the result of part (a), the volume is

\displaystyle \frac\pi8 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{256\pi}{15}}}

c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

\dfrac{\sqrt3}4 \left(2(x^2-4)\right)^2 \, \Delta x = \sqrt3 (x^2-4)^2 \, \Delta x

and using the result of part (a) again, the volume is

\displaystyle \int_{-2}^2 \sqrt 3(x^2-4)^2 \, dx = \frac{\sqrt3}4 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{512}{5\sqrt3}}

7 0
2 years ago
35°<br> 50°<br> ?<br> Find the measure of the missing angle:
Marianna [84]

Answer:

i think the answer would be 95 degree. im not absolutley positive though

Step-by-step explanation:

i added 35 and 50 and got the sum of 85 then i subtracted 85 from 180 and got 95

feedback is appreciated.

(i'm not gonna beg for brainliest)

4 0
3 years ago
The first two steps in the derivation of the quadratic formula by completing the square are shown below.
lidiya [134]

Answer:C

Step-by-step explanation:

3 0
3 years ago
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