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Arturiano [62]
3 years ago
12

How can x^2=x^2+2x+9 be set up as a system of equations

Mathematics
1 answer:
Nikitich [7]3 years ago
8 0

Answer: \left \{ {{y=x^{2} } \atop {y=x^2+2x+9}} \right.

Step-by-step explanation:

1. As you can see, x^{2} is equal to the other quadratic equation x^2+2x+9.

2. Then, this would the same as write the quadratic equations as following:

y=x^{2}

y=x^2+2x+9

3. And then set them equal to each other, as you can see below:

y=y

Substituting, you obtain:

x^{2}=x^2+2x+9

3. Keeping the above on mind, you can set up the given equations as a system of equations as folllowing:

\left \{ {{y=x^{2} } \atop {y=x^2+2x+9}} \right.

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Option D

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Solve for p: 3/8 +p/8= 3 1/8
Ivenika [448]
Solve for p:
p/8 + 3/8 = 25/8
p/8 + 3/8 = (p + 3)/8:
(p + 3)/8 = 25/8

Multiply both sides of (p + 3)/8 = 25/8 by 8:
(8 (p + 3))/8 = (8×25)/8
(8×25)/8 = (8×25)/8:
(8 (p + 3))/8 = (8×25)/8
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An orange is shot up into the air with a catapult. The function h given by
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Answer:

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Step-by-step explanation:

h(t) = 15 + 60t – 16t2

Time t = 1 second

Let's substitute time into the equation to get the distance

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