How can x^2=x^2+2x+9 be set up as a system of equations

Mathematics

1 answer:

Nikitich [7]3 years ago

8 0

Answer: $\left \{ {{y=x^{2} } \atop {y=x^2+2x+9}} \right.$

Step-by-step explanation:

1. As you can see, $x^{2}$ is equal to the other quadratic equation $x^2+2x+9$ .

2. Then, this would the same as write the quadratic equations as following:

$y=x^{2}$

$y=x^2+2x+9$

3. And then set them equal to each other, as you can see below:

$y=y$

Substituting, you obtain:

$x^{2}=x^2+2x+9$

3. Keeping the above on mind, you can set up the given equations as a system of equations as folllowing:

$\left \{ {{y=x^{2} } \atop {y=x^2+2x+9}} \right.$

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3 years ago

Please help with 1 & 2

yaroslaw [1]

First question:

I urge you to perform the division using the synthetic division method:

________________
-4 / 1 3 -6 -6 8
-4 4 8 -8
-----------------------
1 -1 -2 2 0

Note that there is no remainder. When this is the case, the divisor (here, that's -4) is a root of the given polynomial, and the value of that polynomial, g(-4), is 0.

If the remainder were not 0, then the remainder represents the value of the polynomial for that particular divisor. For example, if x = -3, the remainder is -28. We'd write that as g(-3) = -28.

But here, g(-4) = 0.

6 0

3 years ago

Question 18

ira [324]

Answer:

The function which represents this sequence will be:

$a_n=-15n+110$